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Don’t be confused by the 1111...since it appears in both it can be factored out.
Now the GCF of 1111...(100 ones and 60 ones) meaning the highest number of divisors for both 100 and 60
Next give the prime factorization for 100= 2^(2) x 5^(2) and 60=2^(2) x 3 x 5
Now GCD=2^(2)x5=20 Therefore 111...Twenty ones
Ans is (C)

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