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Can someone help me understand how statement 1 not sufficient.
\({9}^2- {3}^2 = 72\) the number has to be 93, how can be assume the number could also be 39 because 9-81=-72.

Or are we assuming \(({-9})^2 - ({-3})^2 = 72\) that's why Statement 1 is insufficient.
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chetan2u, Bunuel, VeritasKarishma, nick1816 can someone help me with my doubt ?
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GMAT Focus 1: 735 Q90 V89 DI81
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kntombat
chetan2u, Bunuel, VeritasKarishma, nick1816 can someone help me with my doubt ?


HI

It does not say that square of tens digit - square of units digit is 72.
It just tells us that \(a^2-b^2=72\). The number could be ab or ba.
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Bunuel
Find the value of the two digit number Z?


(1) The difference in the square of the digits Z is 72.

(2) Z has only four factors, two of which are prime, having a sum of 16.


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(1) The difference in the square of the digits Z is 72.

The square of the digits would vary from 0, 1, 4, 9 ... 64, 81.
If the difference in the squares is 72, 81 must be one of the squares. Then the other square must be 9 because 81 - 9 = 72.
So the digits must be 3 and 9 and the number could be 39 or 93.
Not sufficient.

(2) Z has only four factors, two of which are prime, having a sum of 16.

Z will be the product of two prime factors. Sum of the primes is 16. So the possible combinations are 3*13 = 39 or 5*11 = 55. Not sufficient.

Using both, we see that Z must be 39 because only 39 satisfies both statements.
Answer (C)
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kntombat
Can someone help me understand how statement 1 not sufficient.
\({9}^2- {3}^2 = 72\) the number has to be 93, how can be assume the number could also be 39 because 9-81=-72.

Or are we assuming \(({-9})^2 - ({-3})^2 = 72\) that's why Statement 1 is insufficient.


Question states difference in squares of digits only, does not specify which is larger
smaller. so the number can be both 93 and 39

Posted from my mobile device
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