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Five machines at a certain factory operate at the same constant rate

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Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 24 May 2016, 23:19
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Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 25 May 2016, 01:19
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3
Total work done by 4 machines = 30 * 4 = 120 units

When one more machine is added each machine works for --> 120/5 = 24 hours

Difference = 30 - 24 = 6hrs

Answer: C
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 25 May 2016, 07:34
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1
nalinnair wrote:
Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24



4 machines do a work in 30 days..
1 machine will do that work in 30*4 days...
5 machines will do it in \(30*\frac{4}{5}= 24..\)
lesser time = \(30-24 = 6\)
C
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 25 May 2016, 07:43
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nalinnair wrote:
Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24


Total work = 4*30 machine hrs

Time taken = 4* 30 /5 => 24 hours...

Thus all five machines, operating simultaneously will take ( 30 - 24 ) 6 hours..

Answer will be (C) 6

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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 25 May 2016, 08:40
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nalinnair wrote:
Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24


If 4 machines take 30 hrs, 5 machines will take 30*4/5= 24 hrs

How many fewer hours will all five machines take= 30-24= 6 hrs

C is the answer
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 08 Jan 2017, 00:50
nalinnair wrote:
Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24



Let the rate of machine be x hours. So in hour it can complete 1/x of work. Four machine rate = 4*(1/x) = 4/x.
Now, Rate* Time = Job i.e. 4/x*30 = Job. So one machine can take 120 hour to complete the job.
Five machine works together it can take :120/5 = 24 hours to complete the job.
Hence 30-24 = 6 hours.

Answer is C.
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Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 20 May 2018, 20:29
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Hi VeritasPrepKarishma chetan2u niks18 gmatbusters Bunuel

Let me know if my below approach is correct using 'Joint variation'
as discussed here

I have to find number of hrs when machines operating are increased from 4 to 5.
Simple logic says if I increase the no of machines, the no of hrs to complete the same work
will be reduced. Hence if I have initial no. of hrs defined, I need to multiply it by proper fraction
ie numerator/denominator < 1

Using above steps:

No of hrs = 30 (when 4 machines are operational)
I need to multiply this by 4/5 since I need a fraction less than 1.
Hence I get 30 * (4/5) = 24 as hrs required when 5 machines are operational.

I already know that when 4 machines are working, I shall need 30 hrs.
Hence, difference = 30-24 ie 6 hrs.
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 20 May 2018, 20:38
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adkikani wrote:
Hi VeritasPrepKarishma chetan2u niks18 gmatbusters Bunuel

Let me know if my below approach is correct using 'Joint variation'
as discussed here

I have to find number of hrs when machines operating are increased from 4 to 5.
Simple logic says if I increase the no of machines, the no of hrs to complete the same work
will be reduced. Hence if I have initial no. of hrs defined, I need to multiply it by proper fraction
ie numerator/denominator < 1

Using above steps:

No of hrs = 30 (when 4 machines are operational)
I need to multiply this by 4/5 since I need a fraction less than 1.
Hence I get 30 * (4/5) = 24 as hrs required when 5 machines are operational.

I already know that when 4 machines are working, I shall need 30 hrs.
Hence, difference = 30-24 ie 6 hrs.


Yes, absolutely correct.
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Re: Five machines at a certain factory operate at the same constant rate [#permalink]

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New post 22 May 2018, 17:42
3
nalinnair wrote:
Five machines at a certain factory operate at the same constant rate. If four of these machines, operating simultaneously, take 30 hours to fill a certain production order, how many fewer hours does it take all five machines, operating simultaneously, to fill the same production order?

(A) 3
(B) 5
(C) 6
(D) 16
(E) 24


The rate of 4 machines is 1/30.

We can let the rate of 5 machines be n and create the equation:

4/(1/30) = 5/n

120 = 5/n

120n = 5

n = 5/120 = 1/24

So it will take 1/(1/24) = 24 hours for the 5 machines to fill the same order and thus it takes 6 fewer hours than if the order were filled by 4 machines.

Answer: C
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Re: Five machines at a certain factory operate at the same constant rate   [#permalink] 22 May 2018, 17:42
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