GMAT Club Official Solution:For a production run, the number of inspection hours required, h, is given by h = 14 + p/80, where p is the number of units produced in the run. If one production run was completed on each of two days, Monday and Tuesday, how many more inspection hours were required for the Tuesday production run than for the Monday production run?Let M be the number of units produced on Monday and T be the number of units produced on Tuesday. Then the inspection hours were:
Monday: 14 + M/80
Tuesday: 14 + T/80
So the difference is:
(14 + T/80) - (14 + M/80) = (T - M)/80
Thus, the question really asks for (T - M)/80.
(1) The ratio of the number of units produced on Tuesday to the number produced on Monday was 3:1.
This gives T : M = 3 : 1, so T = 3M. Therefore,
(T - M)/80 = (3M - M)/80 = 2M/80 = M/40
Since M is unknown, the difference cannot be determined. Not sufficient.
(2) 560 more units were produced on Tuesday than on Monday.
This gives T - M = 560, so:
(T - M)/80 = 560/80 = 7
Sufficient.
Answer: B.