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For all numbers a and b, the operation # is defined by a # b = 2a + 2b

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For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 09:03
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A
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E

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Question Stats:

94% (00:25) correct 6% (00:43) wrong based on 33 sessions

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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 09:31
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15


Here a=6 and b=1

Now 6#1=2*6+2*1+1=12+2+1=15

Ans. (E)
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 10:03
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

\(6 # 1\) , here \(a = 6\) & \(b = 1\)

So, \(a # b = 2*6 + 2*1 + 1\)

Or, \(a # b = 12 + 2 + 1\)

Or, \(a # b = 15\), Thus Answer must be (E)
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 10:29
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15


Given; For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1.

Asked: What is the value of 6 # 1 ?

6 # 1 = 2*6 + 2*1 + 1 = 12 + 2 + 1 = 15

IMO E
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 10:46
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15--> correct

Answer:
a # b = 2a + 2b + 1
6 # 1 = 2*6+2*1+1, as a=6 & b=1
6#1=15
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 15 Oct 2019, 11:42
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 16 Oct 2019, 19:19
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15


6 # 1 = 2(6) +2(1) + 1 = 12 + 2 + 1 = 15

Answer: E
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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New post 22 Oct 2019, 22:12
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b   [#permalink] 22 Oct 2019, 22:12
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