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# For all numbers a and b, the operation # is defined by a # b = 2a + 2b

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Joined: 02 Sep 2009
Posts: 59125
For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 09:03
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5% (low)

Question Stats:

94% (00:25) correct 6% (00:43) wrong based on 33 sessions

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For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 09:31
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

Here a=6 and b=1

Now 6#1=2*6+2*1+1=12+2+1=15

Ans. (E)
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 10:03
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

$$6 # 1$$ , here $$a = 6$$ & $$b = 1$$

So, $$a # b = 2*6 + 2*1 + 1$$

Or, $$a # b = 12 + 2 + 1$$

Or, $$a # b = 15$$, Thus Answer must be (E)
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 10:29
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

Given; For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1.

Asked: What is the value of 6 # 1 ?

6 # 1 = 2*6 + 2*1 + 1 = 12 + 2 + 1 = 15

IMO E
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 10:46
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15--> correct

a # b = 2a + 2b + 1
6 # 1 = 2*6+2*1+1, as a=6 & b=1
6#1=15
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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15 Oct 2019, 11:42
6#1= 2*6 + 2*1 +1 = 12+2+1 =15

Hence E
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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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16 Oct 2019, 19:19
Bunuel wrote:
For all numbers a and b, the operation # is defined by a # b = 2a + 2b + 1. What is the value of 6 # 1 ?

A. 6
B. 7
C. 13
D. 14
E. 15

6 # 1 = 2(6) +2(1) + 1 = 12 + 2 + 1 = 15

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Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b  [#permalink]

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22 Oct 2019, 22:12
Re: For all numbers a and b, the operation # is defined by a # b = 2a + 2b   [#permalink] 22 Oct 2019, 22:12
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