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For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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Updated on: 11 Apr 2013, 04:05
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For any numbers a and b, a#b=a + b  ab. If a#b=0, which of the following CANNOT be a value of b? A. 2 B. 1 C. 0 D. 1 E. 3/2
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Originally posted by Stiv on 05 Jul 2012, 01:33.
Last edited by Bunuel on 11 Apr 2013, 04:05, edited 2 times in total.
Edited the question.




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Re: For any numbers a and b, ab= a + b  ab. If ab=0, which of
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05 Jul 2012, 01:51




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Re: For any numbers a and b, ab= a + b  ab. If ab=0, which of
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05 Jul 2012, 23:55
Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+bab => 2ab=a+b. and then saw bunuel's reply then understood what the question was!



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Re: For any numbers a and b, ab= a + b  ab. If ab=0, which of
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25 Jul 2012, 00:40
asax wrote: Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+bab => 2ab=a+b. and then saw bunuel's reply then understood what the question was! Even I got it wrong...
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Re: For any numbers a and b, ab= a + b  ab. If ab=0, which of
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11 Apr 2013, 03:59
asax wrote: Can someone pls edit the question.? i was wondering where i was going wrong thinking. question was ab=a+bab => 2ab=a+b. and then saw bunuel's reply then understood what the question was! Yes indeed, very annoying..



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Re: For any numbers a and b, ab= a + b  ab. If ab=0, which of
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11 Apr 2013, 04:06



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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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11 Apr 2013, 04:15
Stiv wrote: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of the following CANNOT be a value of b?
A. 2 B. 1 C. 0 D. 1 E. 3/2  for me the fastest way must be the use of answer choices to find the value of a if a will be an integer after putting the value of of b as given in the answer choices then the answer will be correct with no cumbersome calculations & its fast too ....!!
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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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17 Jul 2014, 06:27
Can I do it this way?
I will just plug the number in to see if we can solve for a.
a#b=a+bab and a#b=0
=> a+bab=0
A. b=2 > a=2 B. b=1 > a+1a=0 > 1=0??? C. b=0 > a=0 D. b=1 > a=1/2 E. b=3/2 > a= 3/5
So it's clear that b cannot be 1!



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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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17 Jul 2014, 06:37



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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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01 Jan 2016, 18:24
Use answer choices to see whether a valid value for a can be determined. B shows that 1=0 which is never true, so that is the answer.



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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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18 Mar 2018, 16:45
Hi All, This is an example of a Symbolism question (and you'll likely see 1 on Test Day). The idea is that you'll be given a "made up" math symbol, told what it "means" mathematically and then asked to solve some minor equation. Here, we're told to substitute values in for A and B so that the equation…. A + B  AB = 0 We're asked which of the following answers CANNOT be the value of B? So 4 of the answers are POSSIBLE and one is IMPOSSIBLE. There are a couple of ways to approach this prompt. You could work mathematically or you can TEST THE ANSWERS. I'm going to use the answers to my advantage and find the 4 that are possible solutions and the one the creates an impossible situation: If B = 2, then we'd have... A + 2  2A = 0 2 = A So B COULD be 2 If B = 1, then we'd have… A + 1  A = 0 1 = 0??????? B CANNOT equal 1 At this point, we could stop. I'll show you why the other answers are possible though: If B = 0, then we'd have… A + 0  0 = 0 0 = A So B COULD be 0 If B = 1, then we'd have… A 1 (1)(A) = 0 2A = 1 1/2 = A So B COULD be 1 If B = 2/3, then we'd have… A  2/3 (2/3)(A) = 0 A + 2A/3 = 2/3 5A/3 = 2/3 A = 6/15 So B COULD be 2/3 Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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08 Aug 2018, 08:00
Stiv wrote: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of the following CANNOT be a value of b?
A. 2 B. 1 C. 0 D. 1 E. 3/2 Please find here the simple solution in the picture. Hope it helps. Posted from my mobile device
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1533743971297718472570848051729.jpg [ 2.02 MiB  Viewed 2257 times ]
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For any numbers a and b, a#b=a + b  ab. If a#b=0, which of
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30 Oct 2018, 00:35
Stiv wrote: For any numbers a and b, a#b=a + b  ab. If a#b=0, which of the following CANNOT be a value of b?
A. 2 B. 1 C. 0 D. 1 E. 3/2 Given: a # b = a + b – ab. and a # b = 0i.e. a + b – ab = 0(Adding 1 and subtracting 1 simultaneously in the left part of the equation)i.e. a + b  ab 1 +1 = 0 i.e. a(1b) 1 (1b) = 1 i.e. (a1)*(1b) = 1 i.e. (a1)*(b1) = 1 i.e. either a = 0 and b = 0 or a = 2 and b = 2 or (a, b) = (3, 3/2) in any order etc. Point to be Noted: for \((a1)*(b1) = 1\)to be true none of the parts of equation can be zero i.e. (a1)≠0 as well as (b1)≠0 i.e. a and b can NOT be 1Answer: Option B
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For any numbers a and b, a#b=a + b  ab. If a#b=0, which of &nbs
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