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For any two numbers a and b, the operation a#b is given by the express

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Director
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For any two numbers a and b, the operation a#b is given by the express  [#permalink]

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New post 04 Oct 2018, 10:07
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A
B
C
D
E

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96% (01:23) correct 4% (02:40) wrong based on 28 sessions

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For any two numbers a and b, the operation a#b is given by the expression \(a^2 + 6ab + b^2\). If a#1 = -7, then a could be equal to

A) -3
B) -1
C) -4
D) 2
E) 4
Spoiler: OA

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Re: For any two numbers a and b, the operation a#b is given by the express  [#permalink]

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New post 04 Oct 2018, 10:33
Harshgmat wrote:
For any two numbers a and b, the operation a#b is given by the expression \(a^2 + 6ab + b^2\). If a#1 = -7, then a could be equal to

A) -3
B) -1
C) -4
D) 2
E) 4


\(a^2 + 6a + 1 = -7\)

\(a^2 + 6a + 8 = 0\)

\((a+4) (a+2) = 0\)

\(a = -2\) or \(-4\)

Answer choice C

You could do it by backsolving and picking a number from the answer choice.

If we try a = -4

then \((-4)^2 + 6 * -4 * 1 + 1 = 16 -24 + 1 = -7\)
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Re: For any two numbers a and b, the operation a#b is given by the express   [#permalink] 04 Oct 2018, 10:33
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For any two numbers a and b, the operation a#b is given by the express

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