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correct 9%
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For each of four voting districts (Districts 1 through 4), the graph shows the percent of the voters in that district who voted for each of the three major candidates (Candidates X, Y, and Z) for mayor of a certain town, and the percent who voted for a candidate other than these three.
Select from the drop-down menus the options that create the most accurate statement based on the information provided.
Voters in District 4 were more than three times as likely as voters in District to have voted for Candidate .
For each of four voting districts (Districts 1 through 4), the graph shows the percent of the voters in that district who voted for each of the three major candidates (Candidates X, Y, and Z) for mayor of a certain town, and the percent who voted for a candidate other than these three.
Select from the drop-down menus the options that create the most accurate statement based on the information provided.
Voters in District 4 were more than three times as likely as voters in District to have voted for Candidate . .
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This is a stacked bar graph.
Voters in District 4 were more than three times as likely as voters in District ___ to have voted for Candidate ___.
We need voters of district 4 to be more than thrice as likely as some other distirct to vote for a particular candidate. Looking at the graph, we see that district 4 did not vote more than 3 times any other district for candidate X. Its grey segment of the bar would have been at least 3 times more than the grey segment of some other bar. Same is true for the light blue segment so candidate Y is also not possible. District 4's black segment is much bigger than district 2's black segment. Note that district 4's black segment covers more than 3 intervals of the Y axis while district 2's black segment covers less than 1 interval of the Y axis.
Hence, Voters in District 4 were more than three times as likely as voters in District 2 to have voted for Candidate Z.
This question doesn't look like a correct one. With only percentage how can one understands the number of voters? There is fundamentally wrong.
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They are asking for the probability. The total number of voters in each district is irrelevant.
I can say that in district 4, about 32% probability is that the voter voted for candidate Z while in district 2, there is 9% probability that the voter voted for candidate Z.
Well, %ages are probabilities.. probability of 1/2 means 50% of the time (of the total) so in that case if question was asking for the number of votes than it would have been wrong, but question asks " Voters in District 4 were more than three times as likely" means 3 times the %age or the probability.
sg_mba
This question doesn't look like a correct one. With only percentage how can one understands the number of voters? There is fundamentally wrong.
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