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For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?

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For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?  [#permalink]

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New post 12 Nov 2018, 10:50
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For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?

(1) The median of the set n is more than 2.

(2) The median of the set n is 0.
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Re: For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?  [#permalink]

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New post 12 Nov 2018, 14:43
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shivaleo wrote:
For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?

(1) The median of the set n is more than 2.

(2) The median of the set n is 0.

\(n = \left\{ { - 6, - 4,3,5,6} \right\} \cup \left\{ p \right\}\)

\(p\,\,\mathop > \limits^? \,\,2\)

\(\left( 1 \right)\,\,Me{d_n} > 2\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,p = 3\,\,\,\, \Rightarrow \,\,\,n = \left\{ { - 6, - 4,3,3,5,6} \right\}\,\,\,\,\left( {Me{d_n} = 3} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr
\,{\rm{Take}}\,\,p = 2\,\,\,\, \Rightarrow \,\,\,n = \left\{ { - 6, - 4,2,3,5,6} \right\}\,\,\,\,\left( {Me{d_n} = 2.5} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\, \hfill \cr} \right.\)

\(\left( 2 \right)\,\,\,Me{d_n}\,\, = \,\,\,\left\{ \matrix{
\,{{p + 3} \over 2} > 0\,\,\,{\rm{if}}\,\,2 < p \le 5\, \hfill \cr
\,{{3 + 5} \over 2} > 0\,\,\,{\rm{if}}\,\,\,p > 5 \hfill \cr} \right.\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\left( 2 \right)\,\,{\rm{contradicted}}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,p > 2\,\,{\rm{is}}\,\,{\rm{false}}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\,\,\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?  [#permalink]

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New post 13 Jan 2019, 21:47
shivaleo wrote:
For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?

(1) The median of the set n is more than 2.

(2) The median of the set n is 0.



Dear Moderator,
How can both the statements contradict each other? Hope you will look into this and do the needful. Thank you
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Re: For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?  [#permalink]

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New post 13 Jan 2019, 23:41
stne wrote:
shivaleo wrote:
For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?

(1) The median of the set n is more than 2.

(2) The median of the set n is 0.



Dear Moderator,
How can both the statements contradict each other? Hope you will look into this and do the needful. Thank you


This is a poor quality question, that's why it's marked as such.

On the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other.
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For the given set n={3,6,-4,-6,5,p}, is p>2?  [#permalink]

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New post 01 Mar 2019, 11:14
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For the given set n={3,6,-4,-6,5,p}, is p>2?

I. The median of the set n is more than 2.
II. The median of the set n is 0.
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Re: For the given set n={3,6,-4,-6,5,p}, is p>2?  [#permalink]

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New post 01 Mar 2019, 12:57
kiran120680 wrote:
For the given set n={3,6,-4,-6,5,p}, is p>2?

I. The median of the set n is more than 2.
II. The median of the set n is 0.


IF YOU FIND MY SOLUTION TO BE HELPFUL, PLEASE GIVE ME KUDOS

We are asked if p > 2

(1) the median of set n >2. Lets write all of the elements besides p in ascending order: -6,-4,3,5,6 if p is less than -6, the median would be (-4+3)/2 = -1/2 which is not more than 2. Notice that since (-4+3)/2 = -1/2, our median must be either (3+5)/2 (placing p bertween -4 and 3 or between 5 and 6 or to the right of 6 on the number line) or our median can be (3+p)/2 (placing p between 3 and 5) Suppose p = -3 (between -3 and 3) Then our answer is NO. Suppose p = 7 (to the right of 6) then our answer is YES NS

(2) The median of n is 0. The only way for this to happen, is for the two middle numbers of the set (in ascending order) sum to 0. Since 3 is the 3rd number in ascending order, p must =-3, giving us a definite NO Sufficient

The answer is B
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Re: For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?  [#permalink]

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New post 02 Mar 2019, 04:06
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Re: For the given set n = {3, 6, −4, −6, 5, p}, is p > 2?   [#permalink] 02 Mar 2019, 04:06
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