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Bunuel
Four identical cylinders are to be packed standing upright in the same direction into a rectangular shipping box with dimensions 3 x 12 x 4. What is the maximum possible volume of one of the cylinders?


A. 48π
B. 27π
C. 12π
D. 9π
E. 6.75π

Hi Bunuel, chetan2u,

When in a question its mentioned that the dimension is x*y*z, should we always consider it as - l*b*h (i.e. length =x, breadth = y,height = z).
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rahul16singh28
Bunuel
Four identical cylinders are to be packed standing upright in the same direction into a rectangular shipping box with dimensions 3 x 12 x 4. What is the maximum possible volume of one of the cylinders?


A. 48π
B. 27π
C. 12π
D. 9π
E. 6.75π

Hi Bunuel, chetan2u,

When in a question its mentioned that the dimension is x*y*z, should we always consider it as - l*b*h (i.e. length =x, breadth = y,height = z).

rahul16singh28
I would take sides as any dimensions and would work for maximum possible volume.
Max possible volume is when the entire box is completely filled...
Now four cylinder and 4*3=12
So if I place all four in the base in a straight line and have dimensions 3*12 of base..
I can get four placed one by one and entire height of 4 becomes the height of cylinder.
As cylinder's volume is πr^2h, we have to maximize radius.

But above method we get max radius as 3/2=1.5
So volume = π*(1.5)^2*4=9π
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So chetan2u

How did you take 4×3?

My approach was also the same.. to maximize pi*r^2*h..
We have to max out r but couldn't get any further

Posted from my mobile device
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So chetan2u

How did you take 4×3?

My approach was also the same.. to maximize pi*r^2*h..
We have to max out r but couldn't get any further

Posted from my mobile device

Hi saurabh9gupta

The only way to adjust 4 Cylinders in the Shipping Box is when the Breadth of the Box = 12 and each cylinder diameter will be 3.

Hope it clarifies.
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So chetan2u

How did you take 4×3?

My approach was also the same.. to maximize pi*r^2*h..
We have to max out r but couldn't get any further

Posted from my mobile device

Hi..

We take base as 12*3 so dia of each cylinder is 3 and along the length of 12, we can fit 4 cylinders that makes it 4*3=12
In this arrangement, we use every possible region in the cylinder..
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