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Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11

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Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 05 Mar 2018, 21:46
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Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 05 Mar 2018, 21:47
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 180

(D) 165

(E) 150


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Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 05 Mar 2018, 23:51
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Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180


Time spent during the drive is 5 hours and 30 minutes(as Frank starts driving at 6:15 and arrives his destination at 11:45)

Since he spent an hour for dinner, he would have traveled a total of 4 hours and 30 minutes(at 30 miles/hr)

Therefore, Frank travels a distance of 120 + 15 = 135 miles(Option B) during this time.
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Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 06 Mar 2018, 04:51
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180


Duration of travel = 6:15 p.m. to 11:45 p.m = 5 hours and 30 mins with an hour of stop

So net Duration of travel = 4 hours and 30 minutes = 4.5 hours

Average speed of travel = 30 miles per hour

Distance = Speed X Time

i.e. Distance travelled = 30 * 4.5 = 135 miles


Answer: option B
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Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 06 Mar 2018, 20:25
Total time spent on Journey is 5 Hours and 30 Minutes.

Time spent on travel = 5:30 - 1:00 (Time spent on dinner)

Travel time: 4:30
Speed: 30 Miles / Hour

Distance = Time * Speed = 135 Miles

Ans: B
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Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

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New post 08 Mar 2018, 11:32
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180


The entire trip took 5.5 hours. Since Frank stopped for one hour, his driving time was 5.5 - 1 = 4.5 hours, at a rate of 30 miles per hour.

So the distance between Boxville and Austin is 30 x 4.5 = 135 miles.

Answer: B
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Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11   [#permalink] 08 Mar 2018, 11:32
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