GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 18 Jun 2019, 08:43

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 55668
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

05 Mar 2018, 21:46
00:00

Difficulty:

15% (low)

Question Stats:

82% (01:13) correct 18% (01:04) wrong based on 118 sessions

### HideShow timer Statistics

Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 55668
Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

05 Mar 2018, 21:47
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 180

(D) 165

(E) 150

16. Distance/Rate Problems

For more check below:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread
_________________
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3373
Location: India
GPA: 3.12
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

05 Mar 2018, 23:51
1
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180

Time spent during the drive is 5 hours and 30 minutes(as Frank starts driving at 6:15 and arrives his destination at 11:45)

Since he spent an hour for dinner, he would have traveled a total of 4 hours and 30 minutes(at 30 miles/hr)

Therefore, Frank travels a distance of 120 + 15 = 135 miles(Option B) during this time.
_________________
You've got what it takes, but it will take everything you've got
CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2942
Location: India
GMAT: INSIGHT
Schools: Darden '21
WE: Education (Education)
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

06 Mar 2018, 04:51
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180

Duration of travel = 6:15 p.m. to 11:45 p.m = 5 hours and 30 mins with an hour of stop

So net Duration of travel = 4 hours and 30 minutes = 4.5 hours

Average speed of travel = 30 miles per hour

Distance = Speed X Time

i.e. Distance travelled = 30 * 4.5 = 135 miles

_________________
Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION
Senior Manager
Joined: 31 May 2017
Posts: 339
Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

06 Mar 2018, 20:25
Total time spent on Journey is 5 Hours and 30 Minutes.

Time spent on travel = 5:30 - 1:00 (Time spent on dinner)

Travel time: 4:30
Speed: 30 Miles / Hour

Distance = Time * Speed = 135 Miles

Ans: B
_________________
Please give kudos if it helps

Resources
| | | | |
Target Test Prep Representative
Status: Head GMAT Instructor
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2823
Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11  [#permalink]

### Show Tags

08 Mar 2018, 11:32
Bunuel wrote:
Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11:45 p.m. If he averaged 30 miles per hour and stopped one hour for dinner, how far is Boxville from Austin?

(A) 120

(B) 135

(C) 150

(D) 165

(E) 180

The entire trip took 5.5 hours. Since Frank stopped for one hour, his driving time was 5.5 - 1 = 4.5 hours, at a rate of 30 miles per hour.

So the distance between Boxville and Austin is 30 x 4.5 = 135 miles.

_________________

# Jeffrey Miller

Head of GMAT Instruction

Jeff@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Re: Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11   [#permalink] 08 Mar 2018, 11:32
Display posts from previous: Sort by

# Frank left Austin to drive to Boxville at 6:15 p.m. and arrived at 11

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne