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# Frank the Fencemaker needs to fence in a rectangular yard. He fences

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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 280 square feet. How many feet of fence does Frank use?

Solution -

One side of fence = 40 feet -------1
Other side = Y

40*Y=280 --> Y = 7.

Total fence circumference = 2*(40+7) = 94 ---------2

Fence used frank in 3 sides leaving 40 feet side = 2 - 1 = 94 - 40 =54.
ANS C.
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
Perimeter of a rectangle = 2(l+b) = 280, so, l+b = 140.

Since b<l, and it is given that one side of the lawn equals 40 feet, hence b=40 and l=100.

Total feet of fence used = 2(100) + 40 = 240. Ans E.
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
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Given one side of fence is 40 feet and Area = 280 square feet
40 * side = 280 ==> side = 7
Frank uses (7+7+40 ) feet of fence = 54 feet
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
Bunuel wrote:
Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 280 square feet. How many feet offence does Frank use?

A. 14
B. 47
C. 54
D. 180
E. 240

Kudos for a correct solution.

MANHATTAN GMAT OFFICIAL SOLUTION:

You know that one side of the yard is 40 feet long; call this the length. You also know that the area of the yard is 280 square feet. In order to determine the perimeter, you must know the width of the yard.

A = l*w
280 = 40w
w = 280/40 = 7 feet

Frank fences in the two 7-foot sides and one of the 40-foot sides. 40 + 2(7) = 54.

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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
area of rectangular yard = 280 sq.feet
one side of the rectangle is given as 40
280 = 40 * 7
since width < length
so 7 is the other side of the rectangular yard
feet of fence used by Frank is 7 * 2 + 40 =54 feet
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Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
Bunuel wrote:
Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 280 square feet. How many feet offence does Frank use?

A. 14
B. 47
C. 54
D. 180
E. 240

Kudos for a correct solution.

Fencing required is -

7 + 7 + 40 => 54 feet

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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
Hi,

I was able to get 7 as the width but I am not able to comprehend why we are adding 7 two times. Frank fences in three of four sides. The unfenced side is 40. Shouldn't we add 7 three times instead? I am a bit confused. Please help!

Thanks!
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
3
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We have four sides, 2 with length 7 and 2 with breadth 40(Area is 280, as one side is 40 other side has to be 7)
In question stem they have said that one of the sides of the yard(which equals 40) doesn't require fencing.

Other 3 sides that requires fencing are 40+7+7 = 54 feet in length(exception of one side that doesn't require fencing)

Hope it helps!
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
pushpitkc wrote:
We have four sides, 2 with length 7 and 2 with breadth 40(Area is 280, as one side is 40 other side has to be 7)
In question stem they have said that one of the sides of the yard(which equals 40) doesn't require fencing.

Other 3 sides that requires fencing are 40+7+7 = 54 feet in length(exception of one side that doesn't require fencing)

Hope it helps!

I got it now, thank you so much! Kudos given!
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Re: Frank the Fencemaker needs to fence in a rectangular yard. He fences [#permalink]
[quote="Bunuel"]Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 280 square feet. How many feet of fence does Frank use?

A. 14
B. 47
C. 54
D. 180
E. 240

40+40+2A = 280
or, 2A = 200
so, A = 100
Total fence = 200+40 = 240