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Gusano97
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Question is to find no of combinations of x,y,z,w

Choosing only 1 letter - 4C1 ways = 4
Choosing only 2 letter - 4C2 ways = 6
Choosing only 3 letter - 4C3 ways = 4
Choosing only 4 letter - 4C4 ways = 1

Total possible combinations = 4+6+4+1 = 15
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Gusano97
From the set of numbers x, y, t, z and w, how many different combinations can we have without the t in them? Ex:. (x,y), (x), (w,z,y,x), etc and (x,y)=(y,x)

A. 10
B. 14
C. 15
D. 16
E. 30

OA:C
Set of numbers formed by using x, y,z and w
Case 1 : Using 1 number only
C(4,1) =4
Case 2 : Using 2 number only
C(4,2) =6
Case 3 : Using 3 number only
C(4,3) =4
Case 4 : Using 4 number only
C(4,4) =1
Total cases :4+6+4+1=15
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Hello from the GMAT Club BumpBot!

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