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Function x%y represents the remainder when a positive integer x is divided by another positive integer y. If a, b, c, d are positive integers and a%b = 6 and c%d = 9, what is the minimum possible value of b x d?
A. 54
B. 60
C. 63
D. 70
E. Greater than 70
A. 54
B. 60
C. 63
D. 70
E. Greater than 70
BongBideshini
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22 Apr 2026, 03:41
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Since (a % b = 6), the remainder must be less than the divisor, so (b > 6). b >= 7
Since (c % d = 9), the remainder must be less than the divisor, so (d > 9). d>= 10
To minimize (\(b \times d),\) use the smallest possible values:
(\(b \times d = 7 \times 10 = 70)\)
Answer: D. 70
Since (c % d = 9), the remainder must be less than the divisor, so (d > 9). d>= 10
To minimize (\(b \times d),\) use the smallest possible values:
(\(b \times d = 7 \times 10 = 70)\)
Answer: D. 70
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