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# Geometry

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Intern
Joined: 09 Mar 2011
Posts: 15

Kudos [?]: 7 [0], given: 3

Location: Mumbai

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26 Aug 2012, 19:15
Pl refer to the attached file for the question.
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File comment: Geometry related question
Geometry.docx [30.51 KiB]

Kudos [?]: 7 [0], given: 3

Senior Manager
Joined: 11 May 2011
Posts: 355

Kudos [?]: 120 [0], given: 46

Location: US

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26 Aug 2012, 19:52
saurabhsingh24 wrote:
Pl refer to the attached file for the question.

As we know that area of equilateral triangle is - \sqrt{3}/4*a^2 where a is the side of a triangle.
Because area is given a \sqrt{3}, hence side of the trianlge is 2.

1/6 area of the above circle = pi*r^2/6 = 2pi/3.
Hence the area of one side of the arc = 2pi/3 - \sqrt{3}
sum of 3 side of the arc = 3(2pi/3 - \sqrt{3})

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Kudos [?]: 120 [0], given: 46

Re: Geometry   [#permalink] 26 Aug 2012, 19:52
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# Geometry

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