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Let's assume that the mixed juice concentrate costs $100 / unit

Day 1

Amount of mixed juice concentrate = 1

Amount of water = 3

Total Amount = 4

Selling price =\(\frac{ 160 }{ 4}\) = $40

Day 2

Amount of mixed juice concentrate = 1

Amount of water = 4

Total Amount = 5

Selling price = $40 * 5 = $200

Hence, the profit is 100%

IMO A
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Correct Option A . 100%

Day 1: Person mixed juice concentrate with freely available water in the ratio 1:3
= (juice 1 + water 3 = Mixture 4)
= Juice to Mixture ratio = (1/4)
= In 1000ml Juice is 25% and water is 75%

Day 1: The profit on his investment on juice concentrate was 60%
if CP of Mixture is $10, then selling price will be $16, with 60% profit
which makes juice price 25% CP $10 = $2.5 and
at Mixture SP of $16, juice price becomes $4
Profit of 60% as given in Q

Day 2: Person mixed the same in the ratio 1:4
= (juice 1 + water 4 = Mixture 5)
= Juice to Mixture ratio = (1/5)
= In 1000ml Juice is 25% and water is 75%

Day 2: *sold the drink at the same price as the first day.
SP of Mixture is $16 i.e Juice price is $4 - Fixed
we need to find ratio of juice CP @ 1000ml with ratio 1:5 i.e 20%
CP = $10,
Juice 20% in $10 = $2

[($4 - $2)/ $2]*100 = 100%
Day 2: Profit value on day 2? is 100%

Step to solve :
1. Find ratio of juice in Mixture for Day 1
2. Ratio of Mixture will give you juice ratio in CP
3. SP profit is given, gives you SP for next day
4. find ratio of juice in mixture for Day 2
5. Find CP of juice from SP from day 1
6. difference between Juice CP Day 1 to Day 2 by Day 1 will give you profit for Day 2
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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