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02 Jul 2025, 08:27
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Let’s assume the initial weight of the solution is 100 units (for easy math).
Then:
We are told the new solution is 1% salt, so:
Let the new total weight be x.
Then:
2/x=0.01
⇒x=200
So the final solution weighs 200 units.
Since salt is still 2 units, the remaining 198 units must be water.
Initial water = 98 units
Final water = 198 units
final water to initial water:
198/98=99/49
(D)
Then:
- Salt = 2% of 100 = 2 units
- Water = 98% of 100 = 98 units
We are told the new solution is 1% salt, so:
Let the new total weight be x.
Then:
2/x=0.01
⇒x=200
So the final solution weighs 200 units.
Since salt is still 2 units, the remaining 198 units must be water.
Initial water = 98 units
Final water = 198 units
final water to initial water:
198/98=99/49
(D)
Bunuel
02 Jul 2025, 08:29
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i got D qs response :
I used a number picking strategy, 100 total mixture 2 is salt and 98 is water
now water is added and salt becomes one percent. i ask the question 2 is x % of what ?
2 = x/100 ( x = 200 )
if x = 200, and salt is 2 then water is 198.
therefore new water : old water = 198/98
which is same as 99/49
D
I used a number picking strategy, 100 total mixture 2 is salt and 98 is water
now water is added and salt becomes one percent. i ask the question 2 is x % of what ?
2 = x/100 ( x = 200 )
if x = 200, and salt is 2 then water is 198.
therefore new water : old water = 198/98
which is same as 99/49
D
Bunuel
02 Jul 2025, 08:29
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Bookmarks
At the start salt accounts for 2% of the salt+water mixture's weight.
So the initial weight ratio (Salt:Water) is 2:98
After water is added, salt accounts for 1% of the mixture's weight.
The new weight ratio (Salt:Water) is 1:99
Initially water was present as 49 times salt's weight (98/2)
Now, water is present as 99 times of salt's weight (99/1)
If we assume the salt's absolute weight, which is unchanged, as x, then weight of water initially was 49x, and now it is 99x.
So the ratio of final weight of water to initial weight of water becomes 99x:49x
Simplied to 99:49
So the initial weight ratio (Salt:Water) is 2:98
After water is added, salt accounts for 1% of the mixture's weight.
The new weight ratio (Salt:Water) is 1:99
Initially water was present as 49 times salt's weight (98/2)
Now, water is present as 99 times of salt's weight (99/1)
If we assume the salt's absolute weight, which is unchanged, as x, then weight of water initially was 49x, and now it is 99x.
So the ratio of final weight of water to initial weight of water becomes 99x:49x
Simplied to 99:49
