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Dipan0506
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GMAT Club Olympics 2025 (Day 3): Yesterday, on an audio streaming 03 Jul 2025, 07:44
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We cannot come to a conclusion from both the points .
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GMAT Club Olympics 2025 (Day 3): Yesterday, on an audio streaming 03 Jul 2025, 07:52
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Given n(songs) = 3n(podcasts). Was revenue from songs > podcasts?
(1) average revenue per song stream = x, average revenue per podcast stream = x + 12
so revenue from song stream = (3p)(x), revenue from podcast stream = (p)(x+12). Not sufficient.
(2) total revenue/ (4p)>20 not sufficient
(1) + (2) = (3px + px + 12p)/4p >20
= x+3 >20
= x > 17.
say x = 18
is 3p(18)> p(30)
= 54p > 30p
sufficient.
C is the answer
Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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GMAT Club Olympics 2025 (Day 3): Yesterday, on an audio streaming 03 Jul 2025, 07:58
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songs = 3 x podcasts

Revenues:
songs: Songaverage x songs = Songaverage x 3 x podcasts
podcasts: Podcastaverage x podcasts

Songaverage x 3 x podcasts > Podcastaverage x podcasts

3 x Songaverage > Podcastaverage ?

(1)

Podcastaverage = Songaverage + 12

substituting in 3 x Songaverage > Podcastaverage
Songaverage > 6

Statement (1) alone is insufficient.

(2)

(Songaverage*songs+Podcastaverage*podcasts)/(songs+podcasts) = (Songaverage*3*podcasts+Podcastaverage*podcasts)/(3podcasts+podcasts) = (3*Songaverage+Podcastaverage)/4 > 20
3*Songaverage+Podcastaverage > 80

No info if 3*Songaverage>Podcastaverage

Statement (2) alone is insufficient.

(1)+(2)

Podcastaverage=Songaverage+12
3*Songaverage+Podcastaverage > 80
3*Songaverage+Songaverage+12 > 80
Songaverage > 17

Songaverage is greater than 6, so sufficient

Statement (1) and (2) together are sufficient

Answer C
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GMAT Club Olympics 2025 (Day 3): Yesterday, on an audio streaming 03 Jul 2025, 16:13
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Hi Bunuel
May I know why I was not awarded kudos for my explanation? Where did I go wrong? Thank you.



SaKVSF16
Question Analysis

let \(avg_s \) be average revenue for songs, and number of songs be \(s \)
let \(avg_p\) be average revenue for podcasts, and number of podcasts be \(p \)

Given: \(3p = s\)

To find : if total revenue for songs > total revenue for podcasts
\(\\
avg_s * s> avg_p > p \\
avg_s * 3p > avg_p * p \\
3 * avg_s > avg_p ---------------------------- I\\
\)
\(Eqn I\) is what we need to confirm

Statement (1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

this tells us that \(avg_p = 0.12 + avg_s\)
Substituting in I
Is \( 3 * avg_s > avg_p\\
>> 3 * avg_s > 0.12 + avg_s \\
>> avg_s > 0.06 ?\\
\)


We have no way of finding out if \(avg_s > 0.06\)
We could have\( avg_s = 0.05\), and \(avg_p = 0.17\)
or \(avg_s = 0.07\) and \(avg_p = 0.19\)

So statement 1 is not sufficient

Statement (2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.

Total number = \(s+p = 4p\)
Total revenue from songs & podcasts = \(s*avg_s + p*avg_p = p*(3avg_s + avg_p) \)

this statement says \(\frac{ p*(3avg_s + avg_p) } {4p} = \frac{ 3avg_s + avg_p } {4} > 0.20\)
\(\\
>> 3avg_s + avg_p > 0.8 \\
\\
\)

Here again we could have \(avg_s = 0.2\), then \(3*avg_s = 0.6 > avg_p = 0.3 \)
and we could have \(avg_s = 0.1\), then \(3*avg_s = 0.3 < avg_p = 0.6 \)

So statement 2 alone is not sufficient

Combining Statement 1 and 2
\(3avg_s + avg_p > 0.8 \) ----- a
\(avg_p = 0.12 + avg_s\) ------ b

substitute b in a
\(\\
3avg_s + 0.12 + avg_s > 0.8 \\
4avg_s > 0.68\\
avg_s > 0.06 \\
\\
\)

This is what we needed to check, and combining statement 1 and 2 gives us the answer

Hence answer is C
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GMAT Club Olympics 2025 (Day 3): Yesterday, on an audio streaming 04 Jul 2025, 00:04
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From Statements 1 and 2 together,

we get a>17.

Because a>17,

12 is lesser than "a".

b = 12 + a = (something lesser than a) + (a).

3a = a + 2(a). On the other hand, (a) + (something lesser than a) is much lesser than this.

Therefore,

b = 12 + a
b < 3a.

This is what we needed. So, clearly, statements 1 and 2 are together sufficient. The answer is choice C.

---
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