Given :- Songs streamed = 3 × Podcasts streamed
- Let P = number of podcasts streamed
- Then 3P = number of songs streamed
Question: Was song revenue > podcast revenue?
Let :
- s = average revenue per song stream
- p = average revenue per podcast stream
Revenue comparison:- Song revenue = 3P × s
- Podcast revenue = P × p
Is 3P × s > P × p?
i.e Is 3s > p?
Statement (1): p = s + 12 centsSubstituting into our question: Is 3s > s + 12? Is 2s > 12? Is s > 6?
We don't know the value of s, so we can't determine if it's greater than 6 cents.
case scenarios for Statement (1):- If s = 5 cents, then p = 17 cents: 3(5) = 15 < 17, so podcast revenue is higher
- If s = 10 cents, then p = 22 cents: 3(10) = 30 > 22, so song revenue is higher
Statement (1) alone is insufficient.
Statement (2): Average revenue per stream across both > 20 centsTotal revenue = 3P × s + P × p = P(3s + p)
Total streams = 3P + P = 4P
Average = P(3s + p) / 4P = (3s + p) / 4
So: (3s + p) / 4 > 20
Therefore: 3s + p > 80
This gives us a constraint but doesn't directly answer whether 3s > p.
Statement (2) alone is insufficient.
Both statements together: From (1): p = s + 12
From (2): 3s + p > 80
Substituting:
3s + (s + 12) > 80
4s + 12 > 80
4s > 68
s > 17
Since s > 17, we have: 3s > 3(17) = 51
And p = s + 12 > 17 + 12 = 29
So 3s > 51 and p > 29, but we need to check if 3s > p.
Since p = s + 12 and s > 17
3s > p becomes 3s > s + 12
2s > 12
s > 6
Since we know s > 17, and 17 > 6, we have s > 6.
Therefore: 3s > p, meaning song revenue > podcast revenue.
Answer: Both statements together are sufficient, but neither alone is sufficient.