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songs=3*podcasts

(1)
revenue_song = average_song*songs = average_song*3*podcasts
revenue_podcast = average_podcast*podcasts = (average_song+12)*podcasts

Comparing the two:
average_song*3*podcasts > (average_song+12)*podcasts
3*average_song > average_song+12
average_song > 6

Don't know the exact value of average_song

Statement is insufficient

(2)
average_stream = (average_podcast*podcasts + average_song*songs)/(podcasts + songs) > 20
(average_podcast*podcasts + average_song*3*podcasts)/(podcasts + 3*podcasts) > 20
average_podcast + 3*average_song > 80

Don't know the exact values of average_podcast or average_podcast

Statement is insufficient

(1)+(2)
average_podcast = average_song+12
average_podcast + 3*average_song > 80

average_song + 12 + 3*average_song > 80
4*average_song > 68
average_song > 17

As average_song is greater than 6 (in fact is greater than 17), then revenue_song > revenue_podcast

Both statements are sufficient

The right answer is C
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S1 Let p be number of podcasts meaning 3p will be number of songs.Let revenue per song be x meaning revenue per podcast will be x+12
Total revenue will be 3px+p(x+12) but we do not know either p or x hence insufficient
S2 This means total revenue was atleast 20(3p+p) Again we still do not know either p or x hence insufficient
When you equate 3px+p(x+12)>20(3p+p) you will get the answer hence two statements combined are correct
ANS C
Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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A) A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.

Let number of songs and podcasts streamed be s & p respectively
Given that for yesterday, s = 3p
let Total revenue of songs be m & Total revenue of podcasts be n
then question is if m > n

Statement(1): The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday:
avg for revenue earned per podcast stream = n/p
avg for revenue earned per song stream = m/s
n/p = 12 + m/s
n = p*(12+m/3p)
n = 36p + m
it means n will always be greater than m. Sufficient.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.
This statement is comparing yesterday's revenue for both songs and podcasts to something. "It exceeded 20 cents", we do not know exceeded from what. Not sufficient.
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A) A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.

Let number of songs and podcasts streamed be s & p respectively
Given that for yesterday, s = 3p
let Total revenue of songs be m & Total revenue of podcasts be n
then question is if m > n

Statement(1): The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday:
avg for revenue earned per podcast stream = n/p
avg for revenue earned per song stream = m/s
n/p = 12 + m/s
n = p*(12+m/3p)
n = 36p + m
it means n will always be greater than m. Sufficient.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.
This statement is comparing yesterday's revenue for both songs and podcasts to something. "It exceeded 20 cents", we do not know exceeded from what. Not sufficient.
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C should be the answer.
Songs Streamed = 3x
Podcasts Streamed = x
From statement 1 ,
we can say that , average revenue for Songs = y and
Average revenue for Podcasts = (y+12);

Question is ,
Is total revenues i.e
3xy > x*(y+12)
simplifying we get ,
is y>6 ?
Statement 2 says,
the average revenue per stream, calculated across both songs and podcasts are greater than 20.
Hence we can say that y > 6.
Both the statements are required ; Hence the answer is Option C.

Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

songs =3*podcast streamed

\(s=3*p\)

\(x=\)average revenue per song
\(y=\)average revenue per podcast

is \(sx>py?\) or is \(3px>py\)?


Statement 1: The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

\(y=x+12\)

Revenue from songs \(= 3px\)

Revenue from podcasts \(=p(x+12)=px+12p\)

is \(3px>(px+12p)\)?

Since x is unknown, it is not possible to conclude

Not Sufficient

Statement 2: Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.

Total revenue \(=3px+py=p(3x+y)\)

Total streams \(=3p+p=4p\)

Average revenue per stream \(=\frac{p(3x+y)}{4p}=\frac{3x+y}{4}\)

\(\frac{3x+y}{4}>20\)

\(3x+y>80\)

Not Sufficient

Statements Combined:

\(y=x+12\) & \(3x+y>80\)

\(3x+x+12>80\)

\(4x>68\)

\(x>17\) & \(y>29\)

Revenue from songs \(>3px\) is \(>51p\)

Revenue from podcasts \(>29p\)

\(\text{Revenue from songs} > \text{Revenue from podcasts}\)

Sufficient

Answer: C
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Let:
Songs = 3p
Podcasts =p

Revenue per song stream = r(s)
Revenue per podcast stream = r(p)

We want to know:
Is 3r(s) > r(p)

Statement (1):
r(p) = r(s) + 0.12
Substitute:
==> 3r(s)>r(s)+0.12
==> r(s)>0.06
Can't confirm ⇒ Not sufficient

Statement (2):
Average revenue per stream > 0.20
Total revenue = s*r(s) + p*r(p)
Total streams = s + p = 4p
Therefore average revenue per stream
==>{3r(s) + r(p)} /4
Given:
==> {3r(s) + r(p)}/4 > 0.20
==> 3r(s) + r(p) > 0.8
Not enough to confirm 3r(s) > r(p)⇒ Not sufficient

Combine (1) & (2):
Substitute r(p) = r(s) + 0.12 in statement(2)
==> {4r(s) + 0.12}/4 > 0.20
==> r(s) > 0.17

Now check original question :
3r(s) > r(s)+0.12
==> 2r(s) > 0.12 and since r(s)> 0.17 this is true

Statement(1) and (2) combined together are sufficient

Option C is correct
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Let S = Song Streams, P = Podcast Streams, RS = Revenue Songs, RP = Revenue Podcasts, ARS = Average Revenue per Song, ARP = Average Revenue per Podcast

Proportion S:P = 3:1

Is RS > RP?

Statement 1:
ARP = AVS + 12 cents
Is it sufficient? No, it’s not.

Statement 2:
Average all streams > 20 cents.
It’s sufficient? No, it’s not.

Statements 1 and 2 together:

Because our proportion of S:P:
3ARS + 1ARP > 80 cents
3ARS + 1(ARS + 12) > 80
4 ARS + 12 > 80
4 ARS > 68

ARS > 17 cents
ARP = ARS + 12 > 29 cents

Since our base song average per stream is greater than 17, our “max proportion” of the revenue from podcast to music would be when song was “infinetely close” to 17. 29 cents / 17 cents = only 1.7. That said, for any valid value of revenue per music (and, then, per podcast) we can answer the question. Statements 1 and 2 together are sufficient.

Answer = C.
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S=3P

The question is RS>RP?

RS=AS*S=AS*3*P
RP=AP*P

So, the question is equivalent to 3*AS>AP?

(1)
AP=AS+12

3*AS>AP -> 3*AS>AS+12 -> AS>6

Don't know if AS>6

Insufficient

(2)
AStream = (AS*S+AP*P)/(S+P) = (AS*3*P+AP*P)/(3P+P) = (3*AS+AP)/4 > 20
3*AS+AP > 80

Don't know if 3*AS>AP

Insufficient

(1) and (2)
AP=AS+12
3*AS+AP > 80
3*AS+AS+12 > 80
AS > 17

In (1) we calculated that if AS>6, then the answer is YES. So sufficient.

Sufficient

Correct answer is C
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Number of songs streamed = S
Number of podcast streamed = P
We know that, S = 3P

Average revengue per song = Rs
Total revenue per song = Rs*S = Rs*3P

Average revenue per podcast = Rp
Total revenue per podcast = Rp*P

We need to know, if revenue from song streams greater than its revenue from podcast streams
=> 3Rs > Rp (yes or no)

Given 2 statements:

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.
Rp = Rs + 0.12

Now lets substitute above into tghe inequauty eqn
3Rs > Rs + 0.12
Rs > 0.06

So, if Rs > 0.06, song revenue is greater

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.

Total revenue = 3P*Rs + P*Rp = P*(3Rs+Rp)
Total streams = 3P+P = 4P
With the given statement we see that,
Average revenue per stream = P*(3Rs+Rp) / 4P
= ((3Rs + Rp)/4) > 0.2
=> 3Rs + Rp > 0.8

This doesent satisfy the requirement for if 3Rs + Rp > 0.8

A. Statement (1) alone is sufficient, but statement (2) is not.
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Question Analysis

let \(avg_s \) be average revenue for songs, and number of songs be \(s \)
let \(avg_p\) be average revenue for podcasts, and number of podcasts be \(p \)

Given: \(3p = s\)

To find : if total revenue for songs > total revenue for podcasts
\(\\
avg_s * s> avg_p > p \\
avg_s * 3p > avg_p * p \\
3 * avg_s > avg_p ---------------------------- I\\
\)
\(Eqn I\) is what we need to confirm

Statement (1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

this tells us that \(avg_p = 0.12 + avg_s\)
Substituting in I
Is \( 3 * avg_s > avg_p\\
>> 3 * avg_s > 0.12 + avg_s \\
>> avg_s > 0.06 ?\\
\)


We have no way of finding out if \(avg_s > 0.06\)
We could have\( avg_s = 0.05\), and \(avg_p = 0.17\)
or \(avg_s = 0.07\) and \(avg_p = 0.19\)

So statement 1 is not sufficient

Statement (2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.

Total number = \(s+p = 4p\)
Total revenue from songs & podcasts = \(s*avg_s + p*avg_p = p*(3avg_s + avg_p) \)

this statement says \(\frac{ p*(3avg_s + avg_p) } {4p} = \frac{ 3avg_s + avg_p } {4} > 0.20\)
\(\\
>> 3avg_s + avg_p > 0.8 \\
\\
\)

Here again we could have \(avg_s = 0.2\), then \(3*avg_s = 0.6 > avg_p = 0.3 \)
and we could have \(avg_s = 0.1\), then \(3*avg_s = 0.3 < avg_p = 0.6 \)

So statement 2 alone is not sufficient

Combining Statement 1 and 2
\(3avg_s + avg_p > 0.8 \) ----- a
\(avg_p = 0.12 + avg_s\) ------ b

substitute b in a
\(\\
3avg_s + 0.12 + avg_s > 0.8 \\
4avg_s > 0.68\\
avg_s > 0.06 \\
\\
\)

This is what we needed to check, and combining statement 1 and 2 gives us the answer

Hence answer is C
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Let the number of podcasts streamed be x
Number of songs streamed = 3x

Let the avg Rev per songs and per podcasts be S and P

Is 3x*S> x*P?

S1
P=S+12
For this to be true,
3x*S> x*(S+0.12)
3S>S+0.12
S>0.06
We don't know if average revenue earned per song stream on the platform yesterday > 6 cents
If it is then songs rev is more else podcast's rev is more
Insufficient

S2
No info on the individual split of average revenue earned per song or podcast stream on the platform yesterday
Insufficient

Combined, we have
(3x*S + x*(S+0.12))/4x > 0.20
3S+S+0.12>0/8
4S>0.68
S>0.17
We needed S>0.06. Sufficient

Answer C



Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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Let S and P be the songs and podcasts steamed respectively. Let A and B be the corresponding average revenue respectively.

We are given S=3P and we are to answer if AS>BP or 3PA>BP or 3A>B

Statement 1 - We are given B=12+A. In this case, for 3A to be greater than B, 3A>12+A or A>6. This statement alone is insufficient.

Statement 2 - (AS+BP)/(S+P) > 20

Since S = 3P, we get 3A+B>80

This statement is again insufficient to determine whether 3A>B

Combining both statements, we have 3A + 12 + A > 80 or A > 17.

In statement 1, we saw that for 3A>B, A should be greater than 6. Since we know that A>17, we can answer the question.

Therefore, Option C
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Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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The number of songs streamed = s
The number of podcasts streamed = p
=> s= 3p. (eqn 1)

Revenue from song streams = Rs
Revenue from podcast streams = Rp

Assume,
The average revenue per song stream is rs
The average revenue per podcast stream is rp

To find: Rs>Rp?

Statement 1:
The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.
rp=rs+12
=> Rp= rp*p
Rs= rs*s
=> Rs= (rp-12)*3p (from eqn 1) (eqn 2)
Now depending on the value of rp, the value of revenue will change.
Hence, we are unable to determine clearly whether Rs>Rp.
Not Sufficient.

Statement 2:
Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.
=> rs, rp>20
We cannot determine anything from this information alone.
If rp>>rs, then Rs>Rp might not be the case.
Not Sufficient.

Statements 1 and 2 together:
Here, we know rs,rp>20
We also have the relation which tells us : rp=rs+12
Hence, plugin values and check:
When rp=21
Then Rp= 21*p
rs= 21-12=9
Rs= 9*s
=9*3*p= 27p (greater)

This is true for all values of rp>20.
Sufficient.


ANSWER: Option C.
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Let each song stream earn s cents and each podcast stream earn p cents. Because there were three times as many song streams as podcast streams, song revenue exceeds podcast revenue exactly when 3s is greater than p. Statement 1 tells us that p equals s plus 12, which leads to 3s greater than s plus 12 or s greater than 6, but we cannot tell if s really is above 6. Statement 2 tells us that the average over all streams exceeded 20 cents, giving 3s plus p greater than 80, but that alone does not show whether 3s exceeds p. When we combine them, we substitute p equals s plus 12 into 3s plus p greater than 80, getting 4s greater than 68 or s greater than 17. That makes p greater than 29 and 3s greater than 51, so 3s is indeed larger than p. Only together do the statements prove that song revenue was higher.

Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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Lets assume x podcast streamed and revenue from one song is y cents.
Given: podcast streamed = x , song streamed = 3x

According to statement 1:
Lets equate both revenue first.
3x(y) = x(y + 12)
2y = 12 and y = 6 is a critical point. If is y is less than 6 cents then revenue of songs is lower and if y is greater than 6 cents then revenue of songs is Higher.
Hence, statement 1 is insufficient.

According to statement 2: y is greater than 20, we don't know how much price difference by this. Hence, statement 2 is insufficient.

Combine Statements (1) and (2):

By combining both we are eliminated situation is which y is less than 6 so we are getting a specific answer. Hence, both together are sufficient.

(C) Each statement alone is insufficient, but together they are sufficient.
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If, equations are formed, Given Sn=3Pn. We need to know whether Sr> Pr. From 1st statement we get Pr/Pn-Sr/Sn =12. Clearly insufficient. 2nd says avg exceeded 20 cents, not sufficient again. But if both are used together now, and values substituted , we get to a result that, Sr>Pr
Bunuel
Yesterday, on an audio streaming platform, the number of songs streamed was thrice the number of podcasts streamed. Yesterday, was the platform’s revenue from song streams greater than its revenue from podcast streams?

(1) The average (arithmetic mean) revenue earned per podcast stream on the platform yesterday was 12 cents more than the average revenue earned per song stream on the platform yesterday.

(2) Yesterday, the average revenue per stream, calculated across both songs and podcasts, exceeded 20 cents.


 


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