Last visit was: 11 Jul 2025, 05:39 It is currently 11 Jul 2025, 05:39
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 11 Jul 2025
Posts: 102,634
Own Kudos:
Given Kudos: 98,170
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,634
Kudos: 740,346
 [10]
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 11 Jul 2025
Posts: 102,634
Own Kudos:
Given Kudos: 98,170
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,634
Kudos: 740,346
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
User avatar
SChatrg
Joined: 19 Oct 2020
Last visit: 18 Jun 2024
Posts: 8
Own Kudos:
15
 [3]
Given Kudos: 12
Location: India
WE:Information Technology (Computer Software)
Posts: 8
Kudos: 15
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
JonShukhrat
Joined: 06 Jun 2019
Last visit: 01 Jul 2024
Posts: 313
Own Kudos:
988
 [3]
Given Kudos: 655
Location: Uzbekistan
Posts: 313
Kudos: 988
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
I tried to explain everything in detail in the attached file.
My answe is A
Attachments

9.jpg
9.jpg [ 115.03 KiB | Viewed 3590 times ]

User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 10 Jul 2025
Posts: 11,294
Own Kudos:
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert
Expert reply
Posts: 11,294
Kudos: 41,675
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If x ≠ 0, is x < 1 ?

(1) \(\frac{1}{x}\) is the median of \(\frac{1}{x}\), \(-x^2\) and \(-x^3\).

(2) \(-\frac{1}{x^2}\) is the median of \(-\frac{1}{x^2}\), \(-x\) and \(x^5\).


M36-16

x ≠ 0

(1) \(\frac{1}{x}\) is the median of \(\frac{1}{x}\), \(-x^2\) and \(-x^3\).
\(-x^2\) is always negative, while \(\frac{1}{x}\) and \(-x^3\) will have opposite sign.
When x>0, \(\frac{1}{x}>0\), while \(-x^2\) and \(-x^3\) will be negative. This case is not possible.
Hence x<0.
Sufficient

(2) \(-\frac{1}{x^2}\) is the median of \(-\frac{1}{x^2}\), \(-x\) and \(x^5\).
When x>0, \(-\frac{1}{x^2}<0\), while \(x^5>0\) and \(-x<0\). Always true for x>1.
When x<0, \(-\frac{1}{x^2}<0\), while \(x^5<0\) and \(-x>0\). Always true for x<-1.
Hence, Insufficient


A
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 10 Jul 2025
Posts: 11,294
Own Kudos:
Given Kudos: 333
Status:Math and DI Expert
Products:
Expert
Expert reply
Posts: 11,294
Kudos: 41,675
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
If x ≠ 0, is x < 1 ?

(1) \(\frac{1}{x}\) is the median of \(\frac{1}{x}\), \(-x^2\) and \(-x^3\).

(2) \(-\frac{1}{x^2}\) is the median of \(-\frac{1}{x^2}\), \(-x\) and \(x^5\).


M36-16

x ≠ 0

(1) \(\frac{1}{x}\) is the median of \(\frac{1}{x}\), \(-x^2\) and \(-x^3\).
When x>0, \(\frac{1}{x}>0\), while \(-x^2\) and \(-x^3\) will be negative. This case is not possible.
Hence x<0.
Sufficient

(2) \(-\frac{1}{x^2}\) is the median of \(-\frac{1}{x^2}\), \(-x\) and \(x^5\).
\(-\frac{1}{x^2}\) is always negative, while \(-x\) and \(-x^5\) will have opposite sign.
Thus, the signs of three in increasing order would be (-, -, +), which is possible both when x>0 and when x<0.
Insufficient


A
Moderator:
Math Expert
102634 posts