Last visit was: 08 Sep 2026, 16:55

It is currently 08 Sep 2026, 16:55

Toolkit

Practice Tests

Quantitative Questions

Problem Solving (PS)

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more

Request Expert Reply

Confirm Cancel

Sep 09
Masters' Spotlight Fair
07:00 AM PDT
-
10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway
Sep 09
How Aman Bounced Back from 3 MBA Rejections to Get Into Cambridge
10:00 AM PDT
-
11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application...
Sep 04
BIG NEWS! We’ve been nominated, and we’d love your vote!
10:00 AM EDT
-
11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.

Back to Forum

Create Topic

GMAT Club World Cup 2026 (Day 10): A school sets aside $1,860 to be

1 2 3 4

Mardee

Joined: 22 Nov 2022

Last visit: 19 Aug 2026

Posts: 286

Own Kudos:

248

[1]

Given Kudos: 21

Posts: 286

Kudos: 248

[1]

18 Jul 2026, 05:57

Kudos

Bookmarks

$1860 divided between Arman, Bela and Cora
Each amount deposited at 10% annual simple interest ( r = 0.1)
Arman -> 2yrs
Bela -> 4yrs
Cora -> 5yrs

We need to know Cora's original share

We know that each student's final amount at the end of their years will be same
=> Let the final amount be x
Let Arman Bela and Cora initial amounts be a,b and c

Arman final amount
=> x = a*(1+0.1*2)
=> a = 5x/6

Bela final amount
=> x = b*(1+0.1*4)
=> b = 5x/7

Cora final amount
=> x = c*(1+0.1*5)
=> c = 2x/3

Since 1860 was distributed between the cumulative sum of a b and c

=> 5x/6 + 5x/7 + 2x/3 = 1860
=> 93x/42 = 1860
=> x = 840

Now,
c = 2x/3 = 2*840/3 = 560

C. 560

JollyScale

Joined: 04 Jul 2026

Last visit: 28 Aug 2026

Posts: 55

Own Kudos:

[1]

Location: India

Schools: HBS '27 CBS '27 Stanford '27

GPA: 6.87/7

WE:Marketing (Finance: Diversified Financial Services)

Products:

Schools: HBS '27 CBS '27 Stanford '27

Posts: 55

Kudos: 49

[1]

18 Jul 2026, 06:05

Kudos

Bookmarks

SI

arman: 1 + 10%(2) = 1.2
bela: 1 + 10%(4) = 1.4
cora: 1 + 10%(5) = 1.5

final values are eql, so og shares are inverse proportional:

a : b : c = 1/1.2 : 1/1.4 : 1/1.5

= 35 : 30 : 28

total parts = 93

coras part = 28/93 X 1860

= 28 × 20 is
560

ans is c

Bunuel

A school sets aside $1,860 to be divided among three students: Arman, Bela, and Cora. Each student’s share will be deposited at 10% annual simple interest. Arman’s share will be deposited for 2 years, Bela’s share for 4 years, and Cora’s share for 5 years. If the shares are chosen so that the three deposits have the same value at the end of their respective deposit periods, how much is Cora’s original share?

A. $520
B. $540
C. $560
D. $600
E. $620

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

alamin8

Joined: 24 May 2025

Last visit: 07 Sep 2026

Posts: 183

Own Kudos:

[1]

Given Kudos: 32

Location: Bangladesh

Concentration: Accounting, Technology

Schools: HEC Sept '27 INSEAD Aug '27 UNC '27

GPA: 3.89

Schools: HEC Sept '27 INSEAD Aug '27 UNC '27

Posts: 183

Kudos: 79

[1]

18 Jul 2026, 06:19

Kudos

Bookmarks

We know, annual simple interest, including principal = Px (1 + rate x time)
Therefore, Arman = 1 + 0.10x2 = 1.2 = 12/10 = 6/5
Bela = 1.4 = 14/10 = 7/5
Cora = 1.5 = 15/10 = 3/2
The original deposit will be A:B:C = 1/(6/5): 1/(7/5): 1/(3/2) = 5/6:5/7:2/3
simplifying the fraction, A:B:C = (5/6)*42:(5/7)*42:(2/3)*42 = 35:30:28 = 93
Therefore, Cora = (28/93)*1860 = 28*20 = $560

Answer: C

LibrarianTurtle

Joined: 12 Nov 2024

Last visit: 06 Sep 2026

Posts: 36

Own Kudos:

[1]

Given Kudos: 8

GPA: 3.9

Products:

Posts: 36

Kudos: 24

[1]

18 Jul 2026, 06:21

Kudos

Bookmarks

X=Arman
Y=Bela
Z=Cora
X+Y+Z=1860
$(X*\frac{10}{100}* 2) +X=\frac{12x}{10}$
$(Y*\frac{10}{100}* 4) +Y=\frac{14y}{10}$
$(Z*\frac{10}{100}* 5) +Z=\frac{3Z}{2}$
$\frac{12X}{10}=\frac{14y}{10}=\frac{3Z}{2}$
$12x=14y=15z$
$x=\frac{15z}{12}$
$y=\frac{15z}{14}$
z=z
$\frac{15z}{12}+\frac{15z}{14}+z=1860$
z=560
Ans. C
IMO

redandme21

Joined: 14 Dec 2025

Last visit: 01 Aug 2026

Posts: 157

Own Kudos:

144

[1]

Posts: 157

Kudos: 144

[1]

18 Jul 2026, 06:21

Kudos

Bookmarks

A = Arman
B = Bela
C = Cora

Arman: 10% * 2 years = 20% -> 1.2A = 6A/5
Bela: 10% * 4 years = 40% -> 1.4B = 7B/5
Cora: 10% * 5 years = 50% -> 1.5C = 3C/2

A+B+C = 1860

6A/5 = 3C/2 -> 12A = 15C -> A = 5C/4
7B/5 = 3C/2 -> 14B = 15C -> B = 15C/14

5C/4 + 15C/14 + C = 1860
35C + 30C + 28C = 28*1860
93C = 28*1860
3*31C = 28*1860
C = 560

IMO C

geocircle

Joined: 14 Dec 2025

Last visit: 27 Jul 2026

Posts: 150

Own Kudos:

143

[1]

Posts: 150

Kudos: 143

[1]

18 Jul 2026, 06:51

Kudos

Bookmarks

Arman will have A + 2*(10% of A) = 1.2*A
Bela will have B + 4*(10% of A) = 1.4*B
Cora will have C + 5*(10% of A) = 1.5*C

1.2A=1.5C
A=15C/12=5C/4

1.4B=1.5C
B=15C/14

A+B+C=1860
5C/4+15C/14+C=1860
(7*5C+2*15C+28)C/28=1860
93C/28=1860
C=28*1860/93=560

Answer C

Nsanghavi

Joined: 08 Jul 2025

Last visit: 29 Aug 2026

Posts: 59

Own Kudos:

[1]

Given Kudos: 20

Products:

Posts: 59

Kudos: 46

[1]

18 Jul 2026, 06:54

Kudos

Bookmarks

Let Arman's Original Share be = A, Bela's Original share = B and Cora's original share = C
Total amout = A+B+C = 1860

As per simple interest formula, after the given years, at a simple interest of 10%, value of
Arman = A (1+0.10*2) = 1.2A
Bela = B (1+0.10*4) = 1.4B
Cora = C (1+0.10*5) = 1.5C

Also, given that 1.2 A = 1.4B = 1.5C
Let x be one share, hence A = x/1.2, B = x/1.4, C = x/1.5
Now x/1.2+x/1.4+x/1.5 = 1860
10x/12+10x/14+10x/15 = 1860
31x/14= 1860
x = 840

We want Cora's share = x/1.5 = 840/1.5 = 560

Option C

chasing725

Joined: 22 Jun 2025

Last visit: 16 Aug 2026

Posts: 240

Own Kudos:

235

[1]

Given Kudos: 6

Location: United States (OR)

Schools: Stanford

Posts: 240

Kudos: 235

[1]

18 Jul 2026, 07:11

Kudos

Bookmarks

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

Arman = x
Bela = y
Cora = z

x + y + z = 1860

Amount Arman has after 2 years = x + 2x/10 = 12x/10

Amount Bela has after 4 years = y + 4y/10 = 14y/10

Amount Cora has after 5 years = z + 5z/10 = 15z/10

Therefore,
12x = 14y = 15z

x = 5/4z

y = 15/14z

5/4z + 15/14z + z = 1860

93z = 1840 * 28

z = 560

Option C

kavyamahajan9

Joined: 09 Jun 2021

Last visit: 16 Aug 2026

Posts: 44

Own Kudos:

[1]

Given Kudos: 1

Posts: 44

Kudos: 40

[1]

18 Jul 2026, 07:14

Kudos

Bookmarks

Option C 560
Sol

Total money - 1860
Interest rate - 10%

Using formula- A =P(1+rt)
So as we know the A is same so taking it as A for all 3 users

For Arman - Pa (1+0.1x2) =A
= 5A/6
For Bela - Pb (1+0.1x4) =A
= 5A/7
For Cora - Pc(1+0.1x5) =A
=2A/3

Total money = 1860 = 5A/6 + 5A/7 + 2A/3
A= 840

Cora's original share - (840 x 2 )/3 = 560

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

topgmat25

Joined: 15 Dec 2025

Last visit: 27 Jul 2026

Posts: 150

Own Kudos:

139

[1]

Posts: 150

Kudos: 139

[1]

18 Jul 2026, 07:23

Kudos

Bookmarks

Arman+Bela+Cora=1860

In 2 years Arman will have 20% more: 1.2*Arman
In 4 years Bela will have 40% more: 1.4*Bela
In 5 years Cora will have 50% more: 1.5*Cora

All the amounts are equal:
1.2*Arman = 1.5*Cora, Arman = 1.5/1.2 * Cora
1.4*Bela = 1.5*Cora, Bela = 1.5/1.4 * Cora

Substituting in the first equation:
1.5/1.2 * Cora + 1.5/1.4 * Cora + Cora = 1860
5*Cora/4 + 15*Cora/14 + Cora = 1860
28*5*Cora/4 + 28*15*Cora/14 + 28*Cora = 28*1860
35*Cora + 30*Cora + 28*Cora = 28*1860
93*Cora = 28*1860
Cora = 560

The answer is C

Parry104

Joined: 30 Oct 2025

Last visit: 07 Sep 2026

Posts: 28

Own Kudos:

[1]

Given Kudos: 3

Location: India

Concentration: Technology, Operations

Schools: ISB '27 IIM NUS '27

GRE 1: Q170 V158 Verified score

GPA: 3.14

Products:

Schools: ISB '27 IIM NUS '27

GRE 1: Q170 V158 Verified score

Posts: 28

Kudos: 26

[1]

18 Jul 2026, 07:29

Kudos

Bookmarks

Given Interest rate = 10% per year.

Let P1, P2, P3 be the principle amounts for Arman, Bela and Cora respectively. And their time periods are 2,4 and 5 years.

End value for Arman = P1 + (P1*2*10)/100 = P1 + 0.2P1 = 1.2P1
End Value for Bela = P2 + (P2*4*10)/100 = P2 + 0.4P2 = 1.4P2
End Value for Cora = P3 + (P3*5*10)/100 = P3 +0.5P3 = 1.5P3

Also P1 +P2+P3 = 1860

We need value of P3

End values of everyone is same => 1.2P1 = 1.4P2 = 1.5P3

P1 = 1.5P3/1.2 = (5/4)P3
P2 = 15P3/14
P3 = P3

Substituting in the total (5/4)P3 + 15P3/14 + P3 = 1860

Solving for P3 we get P3 = 560

Answer C

firefox300

Joined: 15 Dec 2025

Last visit: 27 Jul 2026

Posts: 151

Own Kudos:

140

[1]

Posts: 151

Kudos: 140

[1]

18 Jul 2026, 07:39

Kudos

Bookmarks

arman amount = a
bela amount = b
cora amount = c

a + 0.1a + 0.1a = 1.2a
b + 0.1b + 0.1b + 0.1b + 0.1b = 1.4b
c + 0.1c + 0.1c + 0.1c + 0.1c + 0.1c = 1.5c

a + b + c = 1860
1.2a = 1.5c
1.4b = 1.5c

3 equations an 3 unkonows

a = 15c/12 = 5c/4
b = 15c/14

5c/4 + 15c/14 + c = 1860
93c/28 = 1860
c = 560

The correct answer is C

FlushLoop

Joined: 05 Jul 2026

Last visit: 06 Aug 2026

Posts: 62

Own Kudos:

[1]

Posts: 62

Kudos: 57

[1]

18 Jul 2026, 07:51

Kudos

Bookmarks

Let the common final value of each account be F.

Since the deposits all grow to the same amount:

Arman's money grows by 20%, so his original share is F/1.2

Bela's money grows by 40%, so her original share is F/1.4

Cora's money grows by 50%, so her original share is F/1.5

F/1.2 + F/1.4 + F/1.5 = 1860

5F/6 + 5F/7 + 2F/3 = 1860

(35F + 30F + 28F)/42 = 1860

93F/42 = 1860

F = 840

Cora's original share was: 840/1.5 = 560

Option C

niteshmotwani

Joined: 09 Nov 2025

Last visit: 08 Sep 2026

Posts: 224

Own Kudos:

[1]

Given Kudos: 16

Posts: 224

Kudos: 31

[1]

18 Jul 2026, 08:00

Kudos

Bookmarks

560 is answer

x+x/5 = 7y/5 = 3z/2

186z = 1860*56 so z =560

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.