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Bunuel
A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8?

(1) The probability that the selected participant is not in the materials group is less than 45%.

(2) The probability that the selected participant is not in the reception group is greater than 40%.


 


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The answer is B for me, and this is what I think.

We want to know whether the selected participant is in the reception group is greater than 5/8.
Which means, is P(R) > 0.4?

Assuming probability for selected participant in Planning be P(PL), in Reception be P(R) and in Materials be P(M).

Statement - 1:


Given that P(not M) > 0.45, that means P(M) < 0.45
So, P(PL) + P(R) > 0.45. However, we do not know anything about P(PL) or P(R). P(R) could be more or less than 0.4.
Hence, this is insufficient.

Statement - 2:

Given that P(Not R) > 0.4
This means that P(R) < 0.4

Hence, B alone is sufficient.
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P(R)>5/8?
Option 1: ~p(M)= P(P)+P(R)<45% => P(R)<45% so sufficient alone to answer the question.
Option 2: ~P(R)>40% => P(R)<60% hence sufficient to answer the question
So answer is D
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A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8 or 62.5%.

(1) The probability that the selected participant is not in the materials group is less than 45%.
Not in material group <45%
So probability of being In planning or reception group<45%. So, being in Material group probability must be more than 55%.
So, Reception must be less 45% which is less than 62.5%
Sufficient

(2) The probability that the selected participant is not in the reception group is greater than 40%.
Probability of not being in reception group>40%
Probability of being in reception group must be less than 60% which is less than 62.5%
Sufficient

D
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Here I got option choice D as answer ,,
--- here R , P , M As reception planning and material ,, R > 5/8 =0.625 ,, r + P + M = 1
----- as per statement 1 , not m ,, then R + P < 45 % so we can say R < 0.450 so we can Definitely say that it is a no
------ as per statement 2 , not p ,, then 1 - P > 0.400 so P < 0.600 so we can Here also say that it's a definitely no
-- so ,, here option D is the correct !! if anybody has any better method feel free to share
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My answer is D) Each statement is sufficient.

P+R+M=100%
Is P(R)>5/8 or 62.5%?

1) P(not M)< 45%; means P(M) > 55%. Therefore, P(R) is less than 45%. Ans is No. Sufficient.
2) P (not R) > 40%; means P(R) < 60%. Ans is No. Sufficient.
Bunuel
A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8?

(1) The probability that the selected participant is not in the materials group is less than 45%.

(2) The probability that the selected participant is not in the reception group is greater than 40%.


 


This question was provided by GMAT Club
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The correct answer is D. Each statement is sufficient.

From the question, P+R+M=1
The question asks if the probability of the person selected from the reception group is greater than 5/8.
So, R>5/8. (5/8= 0.625)

Statement 1.
P+R<45%
P+R<0.45

here R<0.45, so it cannot be greater than 0.625. Hence this statement is sufficient.

Statement 2
1-R>40%
1-R>0.4
1-0.4>R
0.6>R

So here as R<0.6 it cannot be R>0.625. We have a firm answer. Thus Statement 2 is sufficient.
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Answer is D

Given that each participant is only assigned to 1 group (P, R or M). Thus there are no overlaps.
What we have to identify is that Probability (R) > 5/8

At this point, looking at the statements it makes sense to convert 5/8 to percentage. It comes up to 62.5%
Thus the actual question is is Probability (R) > 62.5%

Statement 1: Prob. of participant not being in M is less than 45%.
Since there are no overlaps, there are only 2 possibilities - a participant can or cannot be in a particular group. If they are not in a particular group it would mean they are in either of the two other groups.
As per this statement, The max. probability that a particular participant is not in group M is 44.9% (~45%).
Thus, the minimum probability that they are in M is 55.1% (~55%).
That should mean that the combined probability of them being in P or R is not more than 45%.
Since the combined probability is less than 62.5%, we can definitely say that the probability of them being in R is less than 62.5%.
Hence, Statement 1 is sufficient. We can eliminate options B, C and E.

Statement 2: Probability that they are not in R is greater than 40%
Again drawing from the same logic, the person can either be or not be in a group. The minimum probability that the person is not in R is 40.1% (~40%). Thus the max probability that they are in R is 59.9% (~60%). Since this is also less than 62.5%, we can definitely say that the probability of them being in R is less than 62.5%.
Hence, Statement 2 is sufficient. We can eliminate option A.

Thus, answer is (D)
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I am solving this using a fav approach of mine .

Let's suppose , the number of total participants , N =360
So, 360 . 5/8 =225

So , I need to find out if the participants of receptin group is greater than 225 or not.

Statement 1 - here, not in material group means the sum of participants in planning and reception group.

as, 360 . 45% =162
SO, planning group + reception group < 162
hence , if total sum is less than 162 , the number of participants of reception group is surely < 162.
So , answer is no. The probability of the selected person to be in reception group is not greater than 5/8.

Statement 1 is sufficient .



now from statement 2 ,
not in reception group= sum of planning and material grp

360. 40% =144
hence , planning grp + material grp > 144
so , Reception grp < 360-144 = 216

if reception group is less then 216 , then it can not be greater than 225
So , here the ans is also no .

statement 2 is sufficient alone .

so , each statement alone is sufficient to find out that the probability of being in reception group < 5/8.
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The answer is (D), i.e., each statement is sufficient.
Let,
P + R + M = 100% (As it is given as probability)
Q: whether R is greater than 5/8 = 0.625 = 62.5% or R > 62.5%?

S1: If the participant is not from material group, it will be in P + R. Therefore, P + R < 45%. Since two participants equal less than 45%, R is definitely less than 45% and R cannot be greater than 62.5%. Definitely No. Sufficient.
S2. If the participant is not in the reception group is greater than 40%, it will be P + M > 40%. We can say that R < 60%. Hence, R cannot greater than 62.5%. Definitely No. Sufficient.
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Q: P(R)>5/8? or P(R)>62.5%?

i) P(P or R) < 45% implies that P(P) + P(R) < 45% Hence definitively P(R)<45% and is not greater than 62.5%. Sufficient

ii) P(P or M) > 40% implies that P(R)<60% hence it is not greater than 62.5%. Sufficient

Option D is correct
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In the Question it is asked if the percentage of people in reception group is >62.5% ( >5/8 ).

From statement -1, we can infer that no. of people in materials group is >55%. Hence we can infer that, no. of people in reception group can never be 62.5% as the max possible value is only 100-55=45%

Hence statement -1 is sufficient.

From statement -2 : It is given that max no. of participants in reception group is 60%. Hence it cannot be 62.5%.
Thus each statement alone is sufficient.
Bunuel
A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8?

(1) The probability that the selected participant is not in the materials group is less than 45%.

(2) The probability that the selected participant is not in the reception group is greater than 40%.


 


This question was provided by GMAT Club
for the GMAT World Cup Competition

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IMO B
Let M= materials, R= reception, P = planning
Statement 1: P(not in M)<45/100, or 1-P(in R or in P )<45/100 or, P(in R or in P ) >55/100 (11/20)
Since 5/8 > 11/20 which means P(in R or in P) could be less or greater than 5/8. Hence not sufficient
Statemnt 2: P(not R) >40/100 or 1-P(in R) >40/100 pr P(in R) <60/100 or P(in R)<3/5
since 3/5 < 5/8 . Hnece definitely P(in R) is less than 5/8. Hence Sufficient!
Bunuel
A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8?

(1) The probability that the selected participant is not in the materials group is less than 45%.

(2) The probability that the selected participant is not in the reception group is greater than 40%.


 


This question was provided by GMAT Club
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Rewriting the statements

1. P(P U R) less than 45% means no way p(R) will be greater than 5/8 SUFF
2. P(P U M) greater than 40% may mean yes or no depending on values NOT SUFF
Ans A
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Convert the question asked into percentage to make it easier, as we know 1/8 = 12.5% so 5/8 would be 62.5%

Now let us check the statements individually (I would use 'P' for planning group, 'R' for reception group and 'M' for materials group.
Important thing to notice from question - participants are assigned to exactly one group - so there is no overlap and these are independent groups

S1: Probability(Not M) < 45%
So it means Probability(R+M) < 45%
It translates clearly that, Probability(R) cannot be greater than 45% and hence would be less than 62.5%. So it answers the question asked.
SUFFICIENT

S2: Probability(Not R) > 40%
We could also say that Probability(M+P)>40%
Now we could easily say that the probability(R) would be less than 60%. So Probability(R) would be less than 62.5%

We could also analyze the result mechanically too, As Probability(M) + Probability(P) + Probability(R) = 100% , So the Probability(M+P) could be written as 100% - Probability(R),
100% - Probability(R) > 40%
60% > Probability(R)

SUFFICIENT

Hence answer would be D
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The three groups that can be assigned to each participant are: Planning (P), Reception (R) and Materials (M).
Since each participant is assigned to one group, we can say that the collective probability of these three groups is 100%, i.e.,
P + R + M = 100%
We need to find out whether the probability of picking a participant assigned to the reception group when picking one random participant out of the whole lot is greater than 5/8, i.e., is R > 5/8?
And 5/8 = 62.5%
Therefore, we need to establish whether R > 62.5%.

Let's look at statement 1.
The probability that the selected participant is not in the materials group is less than 45%.
This implies P + R < 45%
Therefore, we can safely assume that the probability of selecting a random participant from each of these two groups individually will be less than 45%, i.e., P < 45% and R < 45%. This answers the question of whether R is greater than 62.5% (or 5/8,) the answer being "no", making it sufficient.

Now, let's look at statement 2.
The probability that the selected participant is not in the reception group is greater than 40%.
This implies P + M > 40%
This means R < 60%
This also answers the question of whether R is greater than 62.5%, again the answer being "no," making it sufficient.

Hence, each statement alone is sufficient to answer the question and our final answer is D.
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Let there be P, R, M, need to know P(R) > 62.5%
1. Not in materials in less than 45%, so means P of being R and P is 45 combined, even if R is 45, that is below 62.5%, so answer is no, hence SUFFICIENT.
2. Not in reception is greater than 40%, means being in reception is at most 60%, which is below 62.5% hence answer is no, hence SUFFICIENT.

SO D.
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3 groups : P, R, M
1 participant selected at random from all participants
Question : is P(R) > 5/8?
implies if P(R) > 62.5%?

Option 1) P(Not M) < 45% ---> P(P or R) < 45% ----> P(R) > 62.5% is false

Option 2) P(Not R) > 40% ----> P(R) < 60%) -----> P(R) > 62.5% is false

Both options are independently enough to answer
Option D
Bunuel
A community center is organizing a weekend workshop. Each participant is assigned to exactly one of three groups: planning, reception, or materials. If one participant is selected at random from all the participants, is the probability that the selected participant is in the reception group greater than 5/8?

(1) The probability that the selected participant is not in the materials group is less than 45%.

(2) The probability that the selected participant is not in the reception group is greater than 40%.


 


This question was provided by GMAT Club
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