Answer is D
Given that each participant is only assigned to 1 group (P, R or M). Thus there are no overlaps.
What we have to identify is that Probability (R) > 5/8
At this point, looking at the statements it makes sense to convert 5/8 to percentage. It comes up to 62.5%
Thus the actual question is is Probability (R) > 62.5%
Statement 1: Prob. of participant not being in M is less than 45%.
Since there are no overlaps, there are only 2 possibilities - a participant can or cannot be in a particular group. If they are not in a particular group it would mean they are in either of the two other groups.
As per this statement, The max. probability that a particular participant is not in group M is 44.9% (~45%).
Thus, the minimum probability that they are in M is 55.1% (~55%).
That should mean that the combined probability of them being in P or R is not more than 45%.
Since the combined probability is less than 62.5%, we can definitely say that the probability of them being in R is less than 62.5%.
Hence, Statement 1 is sufficient. We can eliminate options B, C and E.
Statement 2: Probability that they are not in R is greater than 40%
Again drawing from the same logic, the person can either be or not be in a group. The minimum probability that the person is not in R is 40.1% (~40%). Thus the max probability that they are in R is 59.9% (~60%). Since this is also less than 62.5%, we can definitely say that the probability of them being in R is less than 62.5%.
Hence, Statement 2 is sufficient. We can eliminate option A.
Thus, answer is (D)