Last visit was: 08 Sep 2026, 05:17

It is currently 08 Sep 2026, 05:17

Toolkit

Practice Tests

Data Insights Questions

Data Sufficiency (DS)

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more

Request Expert Reply

Confirm Cancel

Sep 04
BIG NEWS! We’ve been nominated, and we’d love your vote!
10:00 AM EDT
-
11:59 PM EDT
We’ve worked incredibly hard to build TTP into the best test prep experience possible, and it would mean a lot to us to win Newsweek’s 2026 Readers’ Choice Award for Best Test Prep. If TTP has helped you, we’d be incredibly grateful for your vote.
Sep 09
Masters' Spotlight Fair
07:00 AM PDT
-
10:00 AM PDT
Meet AdComs and explore top Master’s programs - MiM, MiF, MSc, MSBA and more. - Application Fee Waivers - Free 1-Week of GMAT Club Tests: - Master's Application Toolkit - Grand Prize Giveaway
Sep 09
How Aman Bounced Back from 3 MBA Rejections to Get Into Cambridge
10:00 AM PDT
-
11:00 AM PDT
Three MBA applications. Three rejections. No interview invites. A year later, Aman was admitted to Cambridge Judge, SMU, and IMD. In this episode of MBA Admit Stories, Aman shares how he rebuilt his MBA application...

Back to Forum

Create Topic

GMAT Club World Cup 2026 (Day 4): A cosmetics lab prepared a liquid

1 2 3 4

chan992

Joined: 21 May 2020

Last visit: 19 Jul 2026

Posts: 13

Own Kudos:

[1]

Posts: 13

Kudos: 10

[1]

10 Jul 2026, 05:31

Kudos

Bookmarks

ans : d

1) b/(a+b+c) = 1/5
b/(4/3a+b+c) = 1/6

when solved, b= a/3 =c

2) self-clear

firefox300

Joined: 15 Dec 2025

Last visit: 27 Jul 2026

Posts: 151

Own Kudos:

140

[1]

Posts: 151

Kudos: 140

[1]

10 Jul 2026, 05:47

Kudos

Bookmarks

W = base + fragance + gel
Wafter = base + base/3 + fragance + gel = W + base/3

(1)
fragance/W = 1/5
fragance/Wafter = 1/6

fragance = W/5
fragance = Wafter/6

Wafter = 6W/5

Wafter = W + base/3
6W/5 = W + base/3
W/5 = base/3
base/W = 3/5

Sufficient

(2)
(base + base/3)/Wafter = 2/3
4*base/3 = 2*Wafter/3
4*base = 2*Wafter
2*base = Wafter

Wafter = W + base/3
2*base = W + base/3
5*base/3 = W
base/W = 3/5

Sufficient

The correct answer is D

rajdeep212003

Joined: 11 Dec 2024

Last visit: 07 Sep 2026

Posts: 156

Own Kudos:

[1]

Given Kudos: 17

Location: India

Schools: ISB '27 Kellogg INSEAD MiM '26

Products:

Schools: ISB '27 Kellogg INSEAD MiM '26

Posts: 156

Kudos: 78

[1]

10 Jul 2026, 05:51

Kudos

Bookmarks

Here I got option D as an answer
---- Let B = original base and T = original total
----- Now after increasing the original base by 1 / 3 The new base is 4/3 b and The new total is t + 4/3 b = t'
Now according to statement one , f / t = 1/5 and f / t' = 1/6 so As f is unchanged t / t' = 6 /5 now t / t + 4/3 b = 6/5 ,, b /t = 3/5 - Sufficient
Now according to statement number two ,, 4b /3 / t+b+ 3 = 2/3 so , b / t = 3 / 5 - Sufficient
As both statements sufficient I choose option D
-- Here If anyone has any better explanation feel free to share

Parry104

Joined: 30 Oct 2025

Last visit: 07 Sep 2026

Posts: 28

Own Kudos:

Given Kudos: 3

Location: India

Concentration: Technology, Operations

Schools: ISB '27 IIM NUS '27

GRE 1: Q170 V158 Verified score

GPA: 3.14

Products:

Schools: ISB '27 IIM NUS '27

GRE 1: Q170 V158 Verified score

Posts: 28

Kudos: 26

10 Jul 2026, 05:56

Kudos

Bookmarks

let b = weight of base, f = weight of fragrance, g = weight of gel. Let w be the total weight

b +f + g = w -- > initial case

b + b/3 +f +g = w + b/3 -- > final case

Statement 1

Initial f = 1/5 w
final f = 1/6(w+b/3)
f = f ==> 1/5w = 1/6(w + b/3)

solving for b/w = 3/5 . Statement 1 alone is sufficient

Statement 2
in final case, weight of b/ total weight = 2/3
(b+b/3)/(w+b/3) = 2/3

solving 4b = 2w + 2/3b
b/w = 3/5

Statement 2 alone is sufficient

Each statement alone is sufficient. Option B

kavyamahajan9

Joined: 09 Jun 2021

Last visit: 16 Aug 2026

Posts: 44

Own Kudos:

[1]

Given Kudos: 1

Posts: 44

Kudos: 40

[1]

10 Jul 2026, 06:05

Kudos

Bookmarks

Both Statements are sufficient

sol
Let us assume the total base = 15

So the base liquid was increased by = 1/3

1) After the addition of base liquid , the ratio of F/W decreased from 1/5 to 1/6

so 1/5 of 15 = 15/5 = 3 grams of fragrance
But the F weight did not change but base liquid was added to total weight increasing it by 1/6

so new total weight = 15 + 3 = 18 grams

So base liquid = 18 -15 = 3 grams of base was added

So 1/3 of the base is 3 grams so total base = 3x3 = 9
Ration of base to total weight = 9/15 = 3/5

Statement is sufficient

2) After the addition on base liquid , the ration of weight of base liquid to total = 2/3

let us assume total weight to be 12

So 12 x 2/3 = 8 grams of new base

The original w was increased by 1/3
8 grams is 4/3 of the original base so
6 grams is the original base

So base grew from 6 to 8 grams so 2 grams are added to the , 12- 2 = 10 - original

final ratio = 6/10 = 3/5

Bunuel

A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

AthaniX

Joined: 21 Jun 2026

Last visit: 06 Sep 2026

Posts: 33

Own Kudos:

[1]

Given Kudos: 2

Products:

Posts: 33

Kudos: 27

[1]

10 Jul 2026, 06:14

Kudos

Bookmarks

After addition
Base=4b/3
total=t+b/3

we need b/t?

statement 1
f/t=1/5
f/(t+b/3)=1/6

equate f,

t/5=(t+b/3)/6
solve and we get b/t=3/5

SUFFICIENT

statement 2

given
(4b/3)/(t+b/3)=2/3

this too can be solved to get b/t=3/5
SUFFICIENT

hence both are suffiecient, option D IMO

redandme21

Joined: 14 Dec 2025

Last visit: 01 Aug 2026

Posts: 157

Own Kudos:

144

[1]

Posts: 157

Kudos: 144

[1]

10 Jul 2026, 06:15

Kudos

Bookmarks

total weight before: t1 = b+f+g
ratio before: r1 = b/t1

total weight after: t2 = t1 + b/3
ratio after: r2 = (4b/3)/t2

r1?

(1)
f/t1 = 1/5 -> f = t1/5
f/t2 = 1/6 -> f = t2/6

t1/5 = t2/6 -> t2 = 6t1/5

As t2 = t1 + b/3 -> 6t1/5 = t1 + b/3 -> b = 3t1/5

r1 = b/t1 = 3/5

Sufficient

(2)
r2 = (4b/3)/t2 = 2/3
4b/t2 = 2
t2 = 2b

As t2 = t1 + b/3 -> 2b = t1 + b/3 -> 6b = 3t1 + b -> b = 3t1/5

r1 = b/t1 = 3/5

Sufficient

IMO D

Mardee

Joined: 22 Nov 2022

Last visit: 19 Aug 2026

Posts: 286

Own Kudos:

248

[1]

Given Kudos: 21

Posts: 286

Kudos: 248

[1]

10 Jul 2026, 06:42

Kudos

Bookmarks

We know that,
Liquid formula consists of base liquid, fragrance oil and gel stabilizer
Let,
Weight of base liquid = b
Weight of fragrance oil = f
Weight of gel stabilizier = g

Initial ratio of base liquid = b/ b+g+f

We know that 1/3rd base liquid was added more to the formula.
=> New total weight = 4b/3 + f + g
But we need to find ratio of initial base liquid to the total weight

We are given statements,
STatements(1) -> After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6

Initial fragrance oil ratio
=> f /b+f+g = 1/5
=> b+f+g = 5f. ---- 3

After the addition the fragrance ratio
=> f/(4b/3) + f + g = 1/6
=> 4b/3 + f + g = 6f. ------4

Now subtracting both the equations 3 and 4 we get,
4b/3 + f + g -(b+f+g) = 6f - 5f
=> b = 3f

Substituting this in 3 we get,
3f+f+g = 5f
=> g = f

Initial ratio = 3f/3f+f+f = 3/5

Statement(1) is sufficient

Statement(2) -> After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3

=> (4b/3)/(4b/3)+f+g = 2/3
=> 2b/3 = f + g

Initial Ratio = b/b + (f+g) = b/(b + (2b/3)) = 3/5

Statement (2) is sufficient

D. Each statement alone is sufficient

SRIVISHUDDHA22

Joined: 08 Jan 2025

Last visit: 19 Aug 2026

Posts: 120

Own Kudos:

[1]

Given Kudos: 371

Location: India

Schools: ISB '26

GPA: 9

Products:

Schools: ISB '26

Posts: 120

Kudos: 80

[1]

10 Jul 2026, 06:49

Kudos

Bookmarks

Total formula T= b+f+g we need the old ratio of B/T ??

ST 1 Old ratio of F >> f/T =1/5--eq1 and new ratio f/1/3b+t =1/6 ---eq2 >> f=t/5 substitute in eq 2 gives f/+3t/3>> 3f/b+3t=1/6 gives us 18f=b+3t and we know f=t/5 which gives us 18t/5= b+3t solving b=18t-15t/5 which is b=4t/5 and b/t=3/5

ST 2 4/3B /1/3B+T=2/3 >> 4B=2/3B+2T which gives 10b/3 =3t and b/t=3/5

ans D

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

topgmat25

Joined: 15 Dec 2025

Last visit: 27 Jul 2026

Posts: 150

Own Kudos:

139

[1]

Posts: 150

Kudos: 139

[1]

10 Jul 2026, 07:00

Kudos

Bookmarks

original weight: T = B + F + G
after weight: TA = B + F + G + B/3 = T + B/3

As we need to find B/T then we need to find a relation between TA and T or between TA and B.

(1)
F/T = 1/5
F/TA = 1/6

F = T/5 = TA/6
TA = 6T/5 -> relation between TA and T

TA = 6T/5 = T + B/3
T/5 = B/3
B/T = 3/5

Condition (1) is sufficient

(2)
(4B/3)/TA = 2/3
2B/TA = 1
TA = 2B -> relation between TA and B

2B = T + B/3
6B = 3T + B
5B = 3T
B/T = 3/5

Condition (2) is sufficient

The answer is D

jkkamau

Joined: 25 May 2020

Last visit: 08 Sep 2026

Posts: 285

Own Kudos:

244

[1]

Given Kudos: 147

Location: Kenya

Schools: Jones '26 (A$$)

GMAT 1: 730 Q50 V46 Verified score

GPA: 3.5

Products:

Schools: Jones '26 (A$$)

GMAT 1: 730 Q50 V46 Verified score

Posts: 285

Kudos: 244

[1]

10 Jul 2026, 07:09

Kudos

Bookmarks

Assume base liquid be b, fragrance oil o, and gel stabilizer g. Base liquid changed to 4/3b (Total = b+f+g)
S1 Use the LCM of the fractions which is 30 meaning the initial total weight is 30 and the new weight is 36 and since only b changed it means b changed by 6 so we can find b given that 4/3b-b=6 hence sufficient
S2 This means 4/3b/t+1/3b=2/3. You simplify this and you get 10b=6t meaning b/t=3/5 hence sufficient
Ans D

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

rungtamehul

Joined: 03 Aug 2025

Last visit: 15 Aug 2026

Posts: 26

Own Kudos:

[1]

Given Kudos: 195

Location: India

Concentration: General Management, Strategy

Schools: ISB HEC Sept '27 INSEAD Aug '27

GMAT Focus 1: 705 Q88 V85 DI82 Verified score

GPA: 7.8

Schools: ISB HEC Sept '27 INSEAD Aug '27

GMAT Focus 1: 705 Q88 V85 DI82 Verified score

Posts: 26

Kudos: 20

[1]

10 Jul 2026, 07:19

Kudos

Bookmarks

Let the original weights of Base liquid, Fragrance Oil and Gel be b, f and g respectively
Total weight T = b + f + g

We need to find out the ratio b/T

Lets look at statement 1
Before addition: f/T = 1/5
After addition: f/(T + b/3) = 1/6

Divide both the equations and we would get b/T = 3/5 (Definite value)

Lets look at statement 2 now
After addition: (b + b/3)/(T + b/3) = 2/3
Solve the equation and we would get b/T = 3/5 (Definite value)

Hence option D is the correct answer

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

harishj1996

Joined: 01 Jun 2026

Last visit: 01 Aug 2026

Posts: 38

Own Kudos:

[1]

Given Kudos: 5

Products:

Posts: 38

Kudos: 28

[1]

10 Jul 2026, 07:21

Kudos

Bookmarks

So this one is a tricky question if the method adopted is not understood properly:

Let the total weight ordinarily = B + F + G
W(new) = B + 1/3B + F + G = 4/3B + F + G

Now according to Statement 1:
We need to find the ratio of fragrance oil to the total weight of the formula which decreased from 1/5 to 1/6. Representing this in equation form we get:

F / 4/3B + F + G = 1/6

However, trying to solve this we could not solve for F alone because we are not able to gauge the value of B or G. Hence the Statement No. 1 is insufficient.

Now moving on to Statement 2:

Statement 2 asks us for the ratio of weight of base liquid to the total weight is 2/3. In equation form:

4/3B divided by W(New) = 2/3

2W = 4B
Hence W = 2B.

Now that we have this we incorporate it into the weight formula already derived:

W = 4/3B + F + G
2B = 4/3B + F + G

2B - 4/3B = F + G

2/3B = F + G

We can again incorporate F + G into the Weight formula

W = 4/3B + 2/3B = 2B

So B/W = 1/2 Hence the ratio is 1/2 and using Statement No 2 we can solve the ratio of Base Liquid to the Total weight. Hence Statement 2 is sufficient

niteshmotwani

Joined: 09 Nov 2025

Last visit: 08 Sep 2026

Posts: 224

Own Kudos:

Given Kudos: 16

Posts: 224

Kudos: 31

10 Jul 2026, 07:33

Kudos

Bookmarks

IMO - ANS is C
Given - Base Liquid (x), Fragrance oil (y) & Gel Stabilizer (z) => then Base Liquid is increased to 1/3 so now 1.33x and y& z remain same ask is x/(x+y+z)
Statement 1 give y/x+y+z = 1/5 and y/(1.33x+y+z) =1/6 so we get the ratio of total old to total new but not the ratio of x/old total.
Statement B gives 1.33x/1.33x + y + z = 2/3 so B also insufficient
Combining both will give the required ratio

from Statement B we get 1.33x = 2*(1.33x +y + z)/3 & from statement 1 = > 1.33x +y +z = 6/5 (x+y+z) we can get easily x/x+y+z so ans is C combining both. Thanks!

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

sunshineeee

Joined: 17 May 2020

Last visit: 07 Sep 2026

Posts: 174

Own Kudos:

Given Kudos: 267

Location: Indonesia

Schools: Stern '26 (WL) Tepper '26 (WL) BU'26 (A) Ross '26 Johnson '26

Products:

Schools: Stern '26 (WL) Tepper '26 (WL) BU'26 (A) Ross '26 Johnson '26

Posts: 174

Kudos: 53

10 Jul 2026, 07:36

Kudos

Bookmarks

The question is the ratio of BL : (BL+FO+GS) before the increase (adding 1/3 BS to all)

(1) FO : (BL+FO+GS) -> 1:5 become 1:6 -> meaning we can calculate the increase of BL -> can caculate the initial ratio
Sufficient

(2) BL : (BL+FO+GS) = 2:3 (after the increase) -> cannot decide the comparison before it was added.
Insufficient

So the answer is A.

Bunuel

This question was provided by GMAT Club
for the GMAT World Cup Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.

canopyinthecity

Joined: 12 Jul 2025

Last visit: 08 Sep 2026

Posts: 161

Own Kudos:

106

[1]

Given Kudos: 25

Products:

Posts: 161

Kudos: 106

[1]

10 Jul 2026, 07:39

Kudos

Bookmarks

Given:
B + F + G = T
(4/3)B + F + G = New T

(A)
F/New T = 1/6
F/T = 1/5
Dividing
New T/T = 6/5 =1 + 1/5

This means (1/5T) =(1/3)B which is the increase This is sufficient to identify B/T

(B) (4/3)B by New T = 2/3
=> New T by (4/3)B =3/2
((1/3)B +T) by (4/3)B = 3/2
We can solve ahead hence this is sufficient too

(D) is the answer

Nsanghavi

Joined: 08 Jul 2025

Last visit: 29 Aug 2026

Posts: 59

Own Kudos:

[1]

Given Kudos: 20

Products:

Posts: 59

Kudos: 46

[1]

10 Jul 2026, 07:58

Kudos

Bookmarks

Let the total weight of Base liquid be x, fragrance be y and gel stabilizer be z
Total weight of the solution will be = x+y+z
It is also given that when x/3 is added, y and z remains unchanged - Accordingly, the total of new solution has the weight of = x+y+z+ 1/3 x = Original Weight + 1/3 x
The question has asked us to find the ratio of x/(x+y+z)

Option 1 - After adding 1/3 x, ratio of y/(x+y+z) has changed
Original Ratio = > 1/5 = y/(x+y+z)
New Ratio => 1/6 = y ( x+y +z+ 1/3x)

Since we have 2 equations we can solve to get the answer and hence Statement 1 is sufficient

Option 2 - This mentions that after addition of 1/3x, the ratio of the (x+1/3x)/ (x+y+z+1/3x )= 2/3
This is a little confusing since we don't have 2 equations, we might think that this is not sufficient, but we are not required solve for individual x, y or z, we just want the ratio x/ x+y+z

Accordingly, on simplifying the ratio, we get -> (4x/3)/(4x/3 + y+ z) = 2/3
4x/(4x+3y + 3z) = 2/3
4x/(3(x+y +z)+ x) = 2/3
2x = 2/3 ((x+y+z) +x/3)
x -x/6 =1/3 (x +y +z)
5/6 x = 1/3 (x+y+z)
5/2 x = x+y +z

Hence we are able to get solution, this is also sufficient

Correct answer is Option D