Let the weights of base liquid, fragrance oil and gel stabilizer be b, f and g respectively. Hence, total weight of the formula is b+f+g
We are also given that qty of base liquid was increased by adding 1/3 of the original weight b to the formula. Thus for the new formula, weight of base liquid = 4b/3 and new total weight is (4b/3) + f + g
statement 1: after base liquid was added, the ratio of fragrance oil to total weight reduced from 1/5 to 1/6
This means, in the old formula
f/(b+f+g) = 1/5
Thus,
5f = b+f+g
4f = b+g ______ (1)
Also, in the new formula, f/[(4b/3) + f + g] = 1/6
6f = (4b/3) + f + g
18f = 4b + 3f + 3g ______(multiplying both sides by 3 to remove fraction)
15f = 4b + 3g ________(2)
Multiplying eqn (1) by and then subtracting from (2) we get
3f = b
f = b/3
If we plug this back into eqn (1), we get
4*(b/3) = b + g
b/3 = g
Thus, in the old formula, ratio. of b to b+f+g is given by plugging values of f and g in terms of b we just found.
b/(b + b/3 + b/3) = b/(b + 2b/3) = b/(5b/3) = 3/5
Thus Statement 1 is sufficient. We can eliminate B, C and E options.
Statement 2: After adding the base liquid, the ratio of b to total weight became 2/3
What we are given is,
(4b/3) / [(4b/3) + f + g] = 2/3
Upon simplification, we know that we can get the ratio.
Statement 2 is also sufficient. Hence, we can eliminate A
D is the correct answer choice