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Statement 1:
F went from 1/5 to 1/6
Let fragrance oil be F
Original F = 1/5T (T = total)
After base added, F = 1/6(T+1/3B)
But because the question specifically mentions that the fragrance doesnt change, we can put the orignal fragrance amount qual to the new one.

1/5T = 1/6(T+1/3B), as you can notice there is only B and T and we can now rearrange to B/T, which comes to around 3/5

after i did it, i realised the following, in the gmat exam itself you could just look at the totals, as the total increase only comes from the base oil. What does that mean.
We are told that the fragrance portion goes from 1/5 to 1/6, so therefore, we can say
F initial = Tinitial x 1/5
F final = T final x1/6
Now as no new fragrance is added we can equate both together and get Tfinal/Tinitial = 6/5

subtract from initial and you get 1/5T

the 1/5T increase came only from 1/3B equate the two and get B/T = 3/5

statement 2:
again keep things in terms of B and T

4/3B/(T +1/3B) = 2/3, as the question mentioned after the addition the base liquid became 2/3 of the new total, so the equation we factor in the B and T.

cross multiply and rearrange to get B/T = 3/5

hence D
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Question info:
Original quantities (OGQ) - Base liquid = B, Fragrance oil = F, Gel stabilizer = G, Total = B+F+G
Revised quantities (RQ) - Base liquid = 4B/3, Fragrance oil = F, Gel stabilizer = G, Total = (4B+3F+3G)/3
I can rewrite RQ as - base liquid = 4B, Fragrance oil = 3F, Gel stabilizer = 3G, Total = 4B+3F+3G
Question is asking B/B+F+G (asked EQ)

St1: In the OGQ, F/B+F+G = 1/5 and in RQ = 3F/4B+3F+3G = 1/6
F/B+F+G = 1/5 ----(cross multiply)---> 5F=B+F+G -> B+G=4F (E1) or 4B+4G=16F (E2) (we'll understand in a bit why I did this)
3F/4B+3F+3G = 1/6 ------(cross multiply)---> 18F=4B+3F+3G -> 4B+3G=15F (E3)
If I subtract E3 from E2, I get F=G
Then E1 becomes B+F=4F -> B=3F. Since we have B,G & F in terms of F, we can find what the question is asking. SUFFICIENT

St2: In RQ, 4B/4B+3F+3G = 2/3
Cross multiply 12B=8B+6F+6G -> 4B=6F+6G -> B=1.5F+1.5G=1.5(F+G)
Substitute the value of B in asked EQ and we get 1.5(F+G)/2.5(F+G and hence the final ratio 3/5. SUFFICIENT

Final answer D
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IMO D
Given in Q stem, let weight of base liquid be L & total weight of formula be X
New wt of base liquid = L+1/3 of L = (4/3)L
New wt of formula = X+(1/3)L
Asked : L/X=?
Statement 1: Let wt of fragrance oil be F. then F/X=1/5 & F/(X+(1/3)L)=1/6
Solving X/5 =(X+ L/3)/6, we can find X/L. Sufficinet

Statement 2: (4/3)L/(X+L/3) =2/3 or 4L=2(X+L/3). We can find L/X. Sufficient
Hence D
Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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My answer is D.) Each statement is sufficient.

Ratio of B to total-

Old ratio= [/B+F+G]- To find
New ratio= [4/3B][/4/3B+F+G]

1) [F][/B+F+G] = 1/5 and [F][/4/3B+F+G] =1/6.
Equation F in both the equations,
[b][/B+F+G] = 3/5. Sufficient.

2) [4/3B][/4/3B+F+G] = 2/3.
By solving, we can find the [b][/B+F+G] = 3/5. Sufficient.
[/b][/b]
Bunuel
[b][b]A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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[/b][/b]
[b][b][b]⚠️ Important: GMAT Club does not allow AI-generated posts. AI-generated solutions are not eligible for kudos, and users who post them may face moderation action, including a ban.[/b][/b][/b]
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initial: b:f:g = b+f+g
after: (4/3)b:f:g = (4/3)b+f+g
what is b/(b+f+g)?

I) f/[(4/3)b+f+g] = 1/6 =>
6f = (4/3)b+f+g
5f = (4/3)b+g (i)

f/(b+f+g)=1/5 =>
5f=b+f+g
4f=b+g (ii)

subtract (ii) from (i) =>
f=(1/3)b
b=3f

put into (ii) =>
4f=3f+g
f=g

b/(b+f+g) = 3f/(3f+f+f) = 3f/5f=3/5 sufficient

II) (4/3)b/[(4/3)b+f+g] = 2/3
4b = (8/3)b+2f+2g
12b=8b+6f+6g
4b=6f+6g
(2/3)b=f+g

b/(b+f+g) = b/[b+(2/3)b] = b/(5/3)b = 3/5 sufficient

answer D
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Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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Base liquid = B
Fragrance Oil = F
Gel stabilizer = G

Original formula = B + F + G
New Formula = 4B/3 + F + G

We have to determine B /(B + F + G)

Statement 1
given- F / B + F + G = 1/5 (i)
and F / (4B/3) + F + G = 1/6 (ii)

Subtracting first from 2nd we get
F = B/3 or B = 3F
Putting this in the (i), we get
G= B/3

Putting values of F and G in terms of B in the question,
we are able to get B / B + B/3 + B/3 = 3/5
Hence (1) is SUFFICIENT

Statement 2

given - (4B/3) / (4B/3) + F + G = 2/3
Cross multiply and we get
4B/3 = (F + G)
Putting this in the question ratio, we get

B/ B + 4B/3 = 3/5
Hence (2) is SUFFICIENT

As both 1 and 2 are individually sufficient, Answer is D
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Let's assume the volume of Base Liquid=X, Fragnance = Y and Gel = Z and Total Volume = T
so Before mixing base liquid : X+Y+Z= A
After Mixing base liquid: (4X/3)+Y+Z = (A+X/3)
From Statement 1 :
before mixing: Y/A = 1/5
After Mixing: Y/(A+X/3) = 1/6
By replacing Y = A/5 in above equation we can find value of X/A independently.

From Statement 2:
After Mixing (4X/3)/(A+X/3) = 2/3
Solving the above equation will take us to X/A ratio independently.

So each statement alone is sufficient.
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Assume total weight 100

Base liquid weight---B
Fragrance weight-- F
Gel stabilizer weight- G

Statement-1: Analysis

before addition of more weight liquid, ratio of fragrance/total weight=1/5 i.e., F/100=1/5 i.e., F=20

Suppose W weight of base liquid added and after addition, ratio of fragrance/ new weight=1/6 i.e., F/(100+W)=1/6.. This can be solved and we get the W.

If we Know the Value of W which is 1/3rd of original base liquid weight B. Then we know B also. We know B then we know G also. So we can find anything asked in the question... We don't need to practically solve it to waste time... We know from these equations we can determine. we have only one variable.

Statement-1 sufficient

Statement-2: Let assume W wight of base liquid added.

Then As per this statement, (W+B)/(110+W)=2/3.-- eqn(1)

Also from original equation we know W=B/3--- eqn(2)

This two equations can be solved to find B and W both . We can easily find B/100 after this . We again don't need to solve we know equations are there and can be solved so we can answer

Statement-2 is sufficient.

Hence, Each statement alone is sufficient. Ans- D
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As per A, the concentration becomes 133, if we assume 100 as all three liquids, now F is the same, and we see that F has decreased from 20 to 16.67, so if you understand the B originally was 60 percent. Hence A is sufficient on its own. For B, we see that 66.67 becomes the actual percentage, if we had 33 percentage of the original one, we see that originally it was 60 percent. Which is the same answer. Hence D, each is sufficient on its own.
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If the total is t, Base is b, after the base increase the base becomes: b+1/3b = 4/3b.
Total becomes t + 1/3 b.

If we have b/t we are good to go.

Statement 1:
SInce Fragrance amount doesnt change but ratio changes from 1/5 to 1/6 so new total t' has to be 6/5 times the old total.
So t + 1/3b = t'
now replacing t' with 6/5t we get
b/t = 3/5
So its sufficient.

Statement 2:
After the increase:
((4/3) b)/(t + 1/3b) = 2/3
So easily simplifying and solving this also gives b/t = 3/5

So IMO ans is D.


Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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Let T = Original weight and B = Original base liquid weight

After increasing the Base Liquid by 1/3, the new total is --> T1 = T +B/3

The question is to find - B/T ?

S1 - Fragrance oil changes from 1/5 to 1/6 of the mixture.

F = T/5
(T/5) / (T + (B/3) = 1/6
6(T/5)= T +B/3
T/5 = B/3
B/T = 3/5

S1 --> Sufficient

S2 - After the increase, the base liquid is 2/3 of the mixture.

(4B/3) / (T + (B/3) = 2/3
Let x = B/T
(4x/3) / (1 +x/3) = 2/3
x = 3/5
B/T = 3/5

S2 --> Sufficient


Answer D - Both statements are individually sufficient.
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Base liquid(x) and Fragrance oil(y) and gel stabilizer(z).
x+y+z= 1
Now, if x is increased by x/3 so x=> x+x/3 =>4x/3
total becomes = 4x/3 + y + z
Question: we need to find x/total => x/(x+y+y) =?

1)Before adding y concentration => y/(x+y+z) = 1/5
after adding x/3 it becomes,
y/(4x/3 + y + Z) = 1/6 let's solve further.
=> 4x/3+y+z = 6y => 4x + 3y + 3z = 18y
=> x+3(x+y+z) =18y
now divide by total (x+y+z)
x/(x+y+z) + 3 = 18y/ (x+y+z) we know y/(x+y+z) =1/5
so x/(x+y+z) = 18/5 - 3= 3/5. Sufficient. (don't need to solve all along once we know we can deduce the value required)

2) After adding x/3, x=> 4x/3
Ratio becomes (4x/3)/(4x/3 +y+z) = 2/3
=> 3(4x/3) = 2(4x/3 +y+z)
4x= 8x/3 + 2y + 2z => 2x = 4x/3 +y+z
=> 6x = 4x + 3y +3z => 5x = 3(x+y+z)
=>x/(x+y+z) = 3/5. Sufficient.

So Answer should be D.
Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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Before the increase,
Base liquid/Total
Given information, increase 1/3 base liquid.

S1: Fragrance oil will be 1/6 from 1/5 due to the increase of 1/3 base liquid.
So, I used 50 as a test number, as 50/5 = 10 for fragrance. 10 for gel and 30 for base.
Increasing 1/3 will make the base 30/3 = 10 + 30 = 40, while fragrance and gel remain unchanged and the total will be 60. Therefore, 10/60 = 1/6 for fragrance. Sufficient.

S2: Base/Total = 2/3
Again, using 50 as a test number.
10 for fragrance, 10 for gel, 30 for base liquid.
Increasing 1/3 will make the base liquid to 40 and total will be 60. Hence, 40/60 = 2/3. Sufficient.

Answer: D
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Let liquid, fragrance oil, and gel stabilizer be denoted as L, F, and G respectively. And L + G + F = Total denoted as T.

From the stem an increase of 1/3 L equals to new value of 4/3 L. Then new ratio of L to Tl will go form L/T to ( 4/3L )/ ( T+(1/3L) ).

We want to find L/T.

Statement 1.
F/T = 1/5 and F/(T + (1/3L)) = 1/6

1. F/T = 1/5 >> 5F = T

2. F/ (T + (1/3L)) = 1/6 >> 6F = T + 1/3L

3. Sub step 1 F for T in step 2 >> 6F = 5F + 1/3L >> F = 1/3L

4. Sub step 3 F in to statement one F/T = 1/5 >> (1/3L)/T = 1/5 >> L / T = 3/5

Sufficient

Statement 2.

(4/3L) / (T + (1/3L)) = 2/3

Step 1. (4/3L) / (T + (1/3L)) = 2/3 >> 4L = 2T + 2/3L >> 4L - 2/3L = 2T >> 10/3 L = 2T >> L / T = 3 / 5

Sufficient

Each statement alone is Sufficient.

Bunuel
A cosmetics lab prepared a liquid formula that consisted of base . The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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This one is simple, since it increased by \(\frac{1}{3}\) it's a no brainer to assume that \(\frac{2}{3}\) \((\frac{-1}{3})\) represents the total remaining weight in the formula. CORRECT: (2)

Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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Lets assume Total formula weight as w and rest as a, b, c

a/w = ?

two scenarios:
one when a, b, c are weight s
second when 4a/3, b, c

S1 => b/w = 1/5 & b/(w+a/3) = 1/6 => b can be eliminated and we can get a/w ratio easily - sufficient
S2 => (4a/3)/(w+a/3) = 2/3 => we have an equation with a and w a/w can easily be calculated - sufficient

Ans - D

Bunuel
A cosmetics lab prepared a liquid formula that consisted of base liquid, fragrance oil, and gel stabilizer. The weight of the base liquid in the formula was increased by 1/3 by adding more base liquid, while the weights of the fragrance oil and gel stabilizer remained unchanged. Before this increase, what was the ratio of the weight of the base liquid to the total weight of the formula?

(1) After the addition of base liquid, the ratio of the weight of fragrance oil to the total weight of the formula decreased from 1/5 to 1/6.

(2) After the addition of base liquid, the ratio of the weight of base liquid to the total weight of the formula became 2/3.


 


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GamePine
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For statement one, I set up T/5 = x/6 (T original mixture weight and x is new weight) because since the weight of fragrance oil never these values must be equal since they give you the weight of the fragrance.

I then rewrote it to x = (6/5)T. We know that x is equal to T + 1/3 of the base liquid (B), so

(6/5)T = T+ B/3. Moving T over you get B/3 = (6/5)T -T. Multiply both sides by 3, B = (3/5)T, so B/T = 3/5.

Statement 1 is sufficient.

For statement 2

(4B/3)/x = 2/3 -> 4B/3 = 2x/3 -> 4B =2x

We know x = T + B/3 so

4B = 2(T + B/3) = 2T +2B/3 -> 4B - 2B/3 = 2T -> 10B/3 =2T -> B = (3/5)T

B/T = 3/5

Statement 2 is sufficient.

The answer is each statement alone is sufficient.
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