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11 Jul 2026, 06:37
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Again a great question I'm not 100% sure if ans is C or E or maybe I would be fully wrong but in my opinion ans is C
So people are doing survey on 2 interface and it says they will reject on 2 basis CN = 48 & SL = 96 and then ask how many survey respondents?
Statement 1 60 have choose both then total would be 60 + 48 + 96 but we can't say who have said both not liked so unsufficient.
Statement 2 said both liked and unliked is equal and again we can say 2x + 48 +96 but we can get total.
if we combined both we can get total so C is sufficient but if we need to think more deeply how many of them choose 1 and not other ( I feel that count would be cover in 48 + 96 ) but if not that case then E option.
But I'm going with option C . Great question once again.
So people are doing survey on 2 interface and it says they will reject on 2 basis CN = 48 & SL = 96 and then ask how many survey respondents?
Statement 1 60 have choose both then total would be 60 + 48 + 96 but we can't say who have said both not liked so unsufficient.
Statement 2 said both liked and unliked is equal and again we can say 2x + 48 +96 but we can get total.
if we combined both we can get total so C is sufficient but if we need to think more deeply how many of them choose 1 and not other ( I feel that count would be cover in 48 + 96 ) but if not that case then E option.
But I'm going with option C . Great question once again.
Bunuel
11 Jul 2026, 06:39
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Let, Total users be T, users without problems be N, ones with slow loading be W and those with confusing navigation would be C.
Finally, C+W+N=T
given: W= 96, C=48->96+48+N=T->N=T-(96+48)
T-?
Statement (1) N=60->96+48+60=T-> sufficient. So, (B),(C) and (E) are out.
Statement (2) N=(96+48)->2*(96+48)=T->sufficient. So, (A) is out.
Only (D) remains.
Finally, C+W+N=T
given: W= 96, C=48->96+48+N=T->N=T-(96+48)
T-?
Statement (1) N=60->96+48+60=T-> sufficient. So, (B),(C) and (E) are out.
Statement (2) N=(96+48)->2*(96+48)=T->sufficient. So, (A) is out.
Only (D) remains.
Bunuel
11 Jul 2026, 06:53
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"would not use" = 96+48 = 144
If a user would not use the two interfaces, he is included twice in this count.
If a user would not use one interface, he is included once in this count.
If a user would use the two interfaces, he is included zero times in this count.
users who would use only 1 interface + 2*(users who would use neither interface) = 144
Users = users who would use 2 interfaces + users who would use only 1 interface + users who would use neither interface
(1)
users who would use 2 interfaces = 60
Users = 60 + users who would use only 1 interface + users who would use neither interface
Many possible values.
Condition insufficient
(2)
users who would use 2 interfaces = users who would use neither interface
Users = users who would use neither interface + users who would use only 1 interface + users who would use neither interface = users who would use only 1 interface + 2*(users who would use neither interface)
And we know that:
users who would use only 1 interface + 2*(users who would use neither interface) = 144
Users = 144
Condition sufficient
Answer B
If a user would not use the two interfaces, he is included twice in this count.
If a user would not use one interface, he is included once in this count.
If a user would use the two interfaces, he is included zero times in this count.
users who would use only 1 interface + 2*(users who would use neither interface) = 144
Users = users who would use 2 interfaces + users who would use only 1 interface + users who would use neither interface
(1)
users who would use 2 interfaces = 60
Users = 60 + users who would use only 1 interface + users who would use neither interface
Many possible values.
Condition insufficient
(2)
users who would use 2 interfaces = users who would use neither interface
Users = users who would use neither interface + users who would use only 1 interface + users who would use neither interface = users who would use only 1 interface + 2*(users who would use neither interface)
And we know that:
users who would use only 1 interface + 2*(users who would use neither interface) = 144
Users = 144
Condition sufficient
Answer B
