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GMAT Club World Cup 2026 (Day 7): A weekend training program had 75

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redandme21

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15 Jul 2026, 06:38

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MD: morning registered for the data-visualization session
AD: afternoon registered for the data-visualization session
MN: morning not registered for the data-visualization session
AN: afternoon not registered for the data-visualization session
D: total registered for the data-visualization session
N: total not registered for the data-visualization session
M: total morning
A: total afternoon
T: total

T=D+N
75=30+N -> N=45

AN/A?

(1)
MD=(2/5)*M
As MD+MN=M -> MN=(3/5)*M
As MN+AN=N=45 -> AN=45-MN=45-(3/5)*M=(225-3M)/5=(3/5)*(75-M)
As M+A=75 -> A=75-M

AN/A = (3/5)*(75-M)/(75-M) = 3/5 = 60%

Sufficient

(2)
AD=(2/3)*AN
As AD+AN=A -> (2/3)*AN+AN=A -> (5/3)*AN=A

AN/A = 3/5 = 60%

Sufficient

IMO D

ShreyaMittal1609

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15 Jul 2026, 06:53

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My ans is B)
M+A=75 (Total praticipants)
Mx+Ay=30. (participants in data visualisation process)

We need to find= (A-Ax)/A

1) No info about proportion in Afternoon track.- INSUFFICIENT
2) Let number of Afternoon track participants who did not register be 30. Then Ay = 2*30/3 = 20
A= 20+30= 50.
Therefore not registered/Total A= 3/5- SUFFICIENT.

Bunuel

A weekend training program had 75 participants, each assigned to exactly one of two tracks: the morning track or the afternoon track, with at least one participant assigned to each track. If 30 of the 75 participants registered for the data-visualization session, what percentage of the afternoon-track participants did not register for the data-visualization session?

(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.

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geocircle

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15 Jul 2026, 07:00

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75 participants and 30 registered: 45 not registered

(1)
morning: 2/5 registered, 3/5 not registered

ratio not registered/registered in morning is 3/2
ratio not registered/registered in total 45/30=3/2

we can conclude that there must be the same ratio in afternoon for not registered/registered: 3/2
not registered afternoon = 3x
registered afternoon = 2x
total afternoon = 5x

not registered afternoon/total afternoon = 3x/5x = 3/5: 60%

Condition sufficient

(2)
afternoon:
not registered afternoon = x
registered afternoon = 2x/3
total afternoon = 5x/3

not registered afternoon/total afternoon = x/(5x/3) = 3/5: 60%

Condition sufficient

Answer D

DishaSaha

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15 Jul 2026, 07:13

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	MT	AT	Total
DVS	a(2x/5)	c (2z/3)	30
NDVS	b(3x/5)	d (z)	45
Total	x	y	75

Analysing only question,
We get the info written in black ink in the table. And we need to find out, c/y*100%?

Evaluating statement 1 alone,
we get the info written in red ink in the table.
.: We do not know anything about how x and y related, proportion wise.
.: St 1 iss not sufficient alone.
.: A & D option is eliminated.
.: Option left B, C & E.

Evaluating statement 2 alone,
We get the info written in blue ink.
Now I know. 2z/3+z=y
.: we can find z/y.
.: We can find c/y
.: Statement 2 is alone sufficient.

.: B is the correct answer.

Bunuel

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gaurikhanna17

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15 Jul 2026, 07:14

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IMO : E

DV NO_DV
M
A ?
30 45 75

i) let M = 5y ===> M*DV = 2y and M*NO_DV = 3y

with this we cant find the A * NO_DV
hence not sufficient

ii ) let A=5x ===> A*DV =2x and A*NO_DV = 3x
again we cant find the asked with this data ==> not sufficient

i +ii ====> 3x+3y =45 ====> x+y =15
2x +2y =30====> x+y =15
hence we cant get one single value but many values for(x,y)
hence not sufficient

topgmat25

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15 Jul 2026, 07:21

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75 participants
30 registered for DV
75-30=45 no registered for DV

(1)
morning participants registered for DV = 2/5 * morning participants
morning participants no registered for DV = morning participants - 2/5 * morning participants = 3/5 * morning participants

afternoon participants registered for DV = 30 - morning participants registered for DV = 30 - 2/5 * morning participants
afternoon participants no registered for DV = 45 - morning participants no registered for DV = 45 - 3/5 * morning participants

adding these two:
afternoon participants = 75 - morning participants

afternoon participants no registered for DV/afternoon participants = (45 - 3/5 * morning participants)/(75 - morning participants) = (225 - 3 * morning participants)/(5*(75 - morning participants)) = 3/5
It is independent of the value of morning participants

3/5 is 60%

Condition (1) is sufficient

(2)
afternoon participants registered for DV = 2/3 * afternoon participants no registered for DV

afternoon participants = 2/3 * afternoon participants no registered for DV + afternoon participants no registered for DV = 5/3 * afternoon participants no registered for DV

afternoon participants no registered for DV/afternoon participants = 3/5

3/5 is 60%

Condition (2) is sufficient

The answer is D

firefox300

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15 Jul 2026, 07:41

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p=75
r=30
nr=75-30=45

(1)
m and r = 2/5 of m -> m and nr = 3/5 of m

find values in afternoon:
a and r = 30 - m and r = 30 - 2/5 of m
a and nr = 45 - m and nr = 45 - 3/5 of m

a = a and r + a and nr = 75 - m

a and nr / a = (45 - 3/5 of m) / (75 - m) = (225 - 3m) / (5*(75 - m)) = 3*(75 - m)/(5*(75 - m)) = 3/5 = 60%

Sufficient

(2)
a and r = 2/3 of a and nr

a = a and r + a and nr = 2/3 of a and nr + a and nr = 5/3 of a and nr

a and nr / a = 3/5 = 60%

Sufficient

The correct answer is D

niteshmotwani

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15 Jul 2026, 07:57

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IMO Ans is C-
Ask is to find what percentage of people in afternoon NOT have data sessions
Given out of 75 30 have but we don't now how many in Morning or Afternoon

SO A insufficient then B also insufficient in first look I maybe wrong bcz i solve just by looking and then I feel from combing both we can get Morning x(2/5) + afternoon = 30

So in my opnion ans is C but I'm 100% sure. Thanks!

Bunuel

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15 Jul 2026, 07:59

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75 participants
Each participant assigned to morning track or afternoon track and each assigned to only one out of these 2 tracks

No of morning track participants = B
No of afternoon track participants = A

B+A = 75

No of participants registered for data visualization = 30
=> No of participants not registed = 75 - 30 = 45

We need to know what percentage of afternoon track students didnt register

=> Let the no of afternoon participants who registed be x and who didnt register be y

Statement 1 ->

No of students who registered in morning = 2B/5

=> No of students registered in afternoon = 30 - 2B/5
=> No of students in afternoon = A = 75 - B
=> No of students not registered in afternoon = 75 - B - (30 - 2B/5) = 45 - 3B/5

We need,
Percentage of afternoon track students who didnt register = 45 - (3B/5) / 75 - B = 0.6 = 60%

Statement 1 is sufficient

Statement 2 ->

=> x = 2y/3
=> x: y = 2 : 3

We need,
y/x + y = 3 / (2+3) = 3/5

=> 60% of afternoon students didnt participate

Statement 2 is sufficient

D. Each statement alone is sufficient

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15 Jul 2026, 08:07

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M=morning track
A=afternoon track
M+A = 75

DV = 30
Non DV 45

Question asked: % of A that did not register for DV? (N in A)

**
(1) 2/5 is DV in M

Insufficient. We do not know the M yet.

(2) In A, DV = 2/3 not DV
Meaning
R=Registered
N=Not registered
R=2/3N
N+2/3N = 5/3 N

Then N in A => 3/5 = 60%

Sufficient. So answer is B.

Bunuel

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