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Difficulty:
95%
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Question Stats:
29% (02:12) correct
71%
(02:40)
wrong
based on 221
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A weekend training program had 75 participants, each assigned to exactly one of two tracks: the morning track or the afternoon track, with at least one participant assigned to each track. If 30 of the 75 participants registered for the data-visualization session, what percentage of the afternoon-track participants did not register for the data-visualization session?
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
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M46-55
Tue Jul 14, 2026 8:00 am
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GMAT Club Official Solution:
A weekend training program had 75 participants, each assigned to exactly one of two tracks: the morning track or the afternoon track, with at least one participant assigned to each track. If 30 of the 75 participants registered for the data-visualization session, what percentage of the afternoon-track participants did not register for the data-visualization session?
Of the 75 participants, 30 registered for the data-visualization session, so the overall fraction who registered was:
30/75 = 2/5
The question asks what percentage of the afternoon-track participants did not register.
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
The overall fraction who registered was 2/5. (1) says that the fraction of morning-track participants who registered was also 2/5.
Since the overall fraction is a weighted average of the morning-track fraction and the afternoon-track fraction, the afternoon-track fraction who registered must also be 2/5. So the fraction of afternoon-track participants who did not register was:
1 - 2/5 = 3/5
Sufficient.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
So among afternoon-track participants:
registered : did not register = 2 : 3
Therefore, the fraction who did not register was:
3/(2 + 3) = 3/5
Sufficient.
Answer: D.
A weekend training program had 75 participants, each assigned to exactly one of two tracks: the morning track or the afternoon track, with at least one participant assigned to each track. If 30 of the 75 participants registered for the data-visualization session, what percentage of the afternoon-track participants did not register for the data-visualization session?
Of the 75 participants, 30 registered for the data-visualization session, so the overall fraction who registered was:
30/75 = 2/5
The question asks what percentage of the afternoon-track participants did not register.
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
The overall fraction who registered was 2/5. (1) says that the fraction of morning-track participants who registered was also 2/5.
Since the overall fraction is a weighted average of the morning-track fraction and the afternoon-track fraction, the afternoon-track fraction who registered must also be 2/5. So the fraction of afternoon-track participants who did not register was:
1 - 2/5 = 3/5
Sufficient.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
So among afternoon-track participants:
registered : did not register = 2 : 3
Therefore, the fraction who did not register was:
3/(2 + 3) = 3/5
Sufficient.
Answer: D.
General Discussion
Tue Jul 14, 2026 7:27 am
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A weekend training program had 75 participants, each assigned to exactly one of two tracks: the morning track or the afternoon track, with at least one participant assigned to each track. If 30 of the 75 participants registered for the data-visualization session, what percentage of the afternoon-track participants did not register for the data-visualization session?
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
plot is 2x2 matrix
--------MT---AT----
DV--- ---- -- ---- 30
NDV-- --- N ----- 45
total--- ---- ------ 75
determine value of N
#1
let MT be x
2x/5 have registered for DV
3x/5 have not registered for DV
AT with DV is 30- 2x/5
AT with NDV is 45-3x/5
AT = 75-x
45-3x/5 / 75-x = 60 %
sufficient statement 1
#2
if A NDV is x then A DV is 2x/3
total A participants 5x/ 3
ratio will be
x/ 5/ 3x = 3/5 = 60%
sufficient statement 2
OPTION D is correct
(1) Of the morning-track participants, 2/5 registered for the data-visualization session.
(2) Among the afternoon-track participants, the number who registered for the data-visualization session was 2/3 of the number who did not register for it.
plot is 2x2 matrix
--------MT---AT----
DV--- ---- -- ---- 30
NDV-- --- N ----- 45
total--- ---- ------ 75
determine value of N
#1
let MT be x
2x/5 have registered for DV
3x/5 have not registered for DV
AT with DV is 30- 2x/5
AT with NDV is 45-3x/5
AT = 75-x
45-3x/5 / 75-x = 60 %
sufficient statement 1
#2
if A NDV is x then A DV is 2x/3
total A participants 5x/ 3
ratio will be
x/ 5/ 3x = 3/5 = 60%
sufficient statement 2
OPTION D is correct
Tue Jul 14, 2026 7:31 am
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Answer: D) each statement alone is sufficient
We're looking for aND/a (afternoon No Data divided by afternoon)
Let's set up a matrix
Morning Afternoon. Total
Data course 2m/5 2x/3 30
No Data course 3m/5 x 45
Total m 5x/3 75
From statement (1):
(45 - 3m/5) / (75 - m) = aND/a ->after factoring 3/5 out of the numerator, (75 - m) cancels out and gives us an answer
From statement (2)
If x = the number of people who didn't register for the data course in the afternoon
x/(5x/3) = 3/5 -> the x cancels out and we have an answer
We're looking for aND/a (afternoon No Data divided by afternoon)
Let's set up a matrix
Morning Afternoon. Total
Data course 2m/5 2x/3 30
No Data course 3m/5 x 45
Total m 5x/3 75
From statement (1):
(45 - 3m/5) / (75 - m) = aND/a ->after factoring 3/5 out of the numerator, (75 - m) cancels out and gives us an answer
From statement (2)
If x = the number of people who didn't register for the data course in the afternoon
x/(5x/3) = 3/5 -> the x cancels out and we have an answer
