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17 Jul 2026, 07:48
Kudos
Bookmarks
4 Day production
2 Shifts -> Morning and Evening
Let
the total no of workers = x
A worker produces y units per shift
Now, Lets simplify and assign the number of workers for each shift based on the passage for each day
Day 1 =>
Morning Shift -> x workers
Evening shift -> 0
Day 2 =>
Morning shift -> 2x/3
Evening shift -> x/3
Day 3 =>
Morning shift -> 4x/9
Evening shift -> 5x/9
Day 4 =>
Morning shift -> 8x/27
Evening shift -> 19x/27
=> Total units produced in 4 days = 4*x*y = 4xy
=> Total units produced in evening shift = y * (0 + x/3 + 5x/9 + 19x/27) = 43xy/27
From this we can say that, total no of workers must be a multiple of 27
=> xy = 27k where k is a +ve integer
=> Total units produced in evening shift = 43k
=> Total units produced in 4 days = 4xy = 108k
=> From the given options only 216 satisfy this
i.e, k = 2
=> Evening shift = 86
=> Both shifts = 216
2 Shifts -> Morning and Evening
Let
the total no of workers = x
A worker produces y units per shift
Now, Lets simplify and assign the number of workers for each shift based on the passage for each day
Day 1 =>
Morning Shift -> x workers
Evening shift -> 0
Day 2 =>
Morning shift -> 2x/3
Evening shift -> x/3
Day 3 =>
Morning shift -> 4x/9
Evening shift -> 5x/9
Day 4 =>
Morning shift -> 8x/27
Evening shift -> 19x/27
=> Total units produced in 4 days = 4*x*y = 4xy
=> Total units produced in evening shift = y * (0 + x/3 + 5x/9 + 19x/27) = 43xy/27
From this we can say that, total no of workers must be a multiple of 27
=> xy = 27k where k is a +ve integer
=> Total units produced in evening shift = 43k
=> Total units produced in 4 days = 4xy = 108k
=> From the given options only 216 satisfy this
i.e, k = 2
=> Evening shift = 86
=> Both shifts = 216
17 Jul 2026, 09:50
Kudos
Bookmarks
I started with looking for numbers dividing by 3 as per explanation for total units.
First 3 got eliminated-
Started with max 216
Over 4 days it will be 54 each
Day - MS - ES
1 - 54 - 0
2 - 36 - 18
3 - 24 - 30
4 - 16 - 38
Total both shifts = 216
Total ES = 86
Reasonable
I checked for 162 which is not divisible by 4 discarded
Last 108 => 27 each
Day - MS - ES
1 - 27 - 0
2 - 18 - 9
3 - 12 -15
4 - 8 - 19
Total both shifts = 108
Total ES = 43 => NA
So (86, 216) is correct
First 3 got eliminated-
Started with max 216
Over 4 days it will be 54 each
Day - MS - ES
1 - 54 - 0
2 - 36 - 18
3 - 24 - 30
4 - 16 - 38
Total both shifts = 216
Total ES = 86
Reasonable
I checked for 162 which is not divisible by 4 discarded
Last 108 => 27 each
Day - MS - ES
1 - 27 - 0
2 - 18 - 9
3 - 12 -15
4 - 8 - 19
Total both shifts = 108
Total ES = 43 => NA
So (86, 216) is correct
17 Jul 2026, 09:58
Kudos
Bookmarks
Bunuel
Let number of workers = x
units per worker = y
| Day | Morning Shift | Evening Shift |
| Day 1 | x | 0 |
| Day 2 | 2x/3 | x/3 |
| Day 3 | 4x/9 | x/3 + 2x/9 |
| Day 4 | 8x/27 | x/3 + 2x/9 + 4x/27 |
Total workers in evening shift = x/3 + (x/3 + 2x/9) + (x/3 + 2x/9 + 4x/27)
= 43x/27 workers
Each worker produces same number of units
Workers in morning + evening = 43/27x + x + 2x/3 + 4x/9 + 8x/27
= 108x/27 = 4x
Total/ evening = 4xy / (43/27xy) = 108/43
We find values from the choices that satisfy this ratio, and we get
Total units = 216
Units in evening shift = 86
