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Answer: D

From the prompt, the cube is built out of 125 unit cubes.
Selecting 1, 2, 3, 4 or 5 cubes at a time, taken
length, breadth and height wise.
Total number of cuboids =
(1+2+3+4+5) ^3 =3375
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we have to find different solution of x+y+z=125
which is (125+3-1)C(3-1)=127C2
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giving a try
for cube of side 5*5*5 ;
now to make a non identical cube we need to get sum of total cubes which can be made
in this case for each side = 5*6/2 ; 15
and for three such sides we have 15^3 ; 3375
IMO D


A 5 × 5 × 5 cube is built using unit cubes. How many different non identical cuboids
can be formed using the same number of unit cubes?
A. 1000
B. 1728
C. 2730
D. 3375
E. 4096
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GMATBusters

GMATBusters’ Quant Quiz Question -9


A 5 × 5 × 5 cube is built using unit cubes. How many different non identical cuboids
can be formed using the same number of unit cubes?
A. 1000
B. 1728
C. 2730
D. 3375
E. 4096

GMATBusters :- Could you please provide an explanation for this problem. Thanks
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GMATBusters

Official Explanation :



To understand the concept, let us take an example of 2-D Rectangle first:


GMATBusters

GMATBusters’ Quant Quiz Question -9


A 5 × 5 × 5 cube is built using unit cubes. How many different non identical cuboids
can be formed using the same number of unit cubes?
A. 1000
B. 1728
C. 2730
D. 3375
E. 4096
Attachment:
Sol2.JPG

GMATBusters :-
Let's take the 6 lines as 1st, 2nd, 3rd, 4th, 5th and 6th

When we take \(6_C_2\) -

Let's take 1st and 2nd of each L, W and H - This will form 1*1*1 cube

If we choose 5th and 6th of each L, W, and H - This will also form 1*1*1 cube

Aren't we considering identical cuboids in such case? How are we eliminating identical ones when we take \(6_C_2\)?
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You are right, there was a typo in the question, I have revised the same to avoid confusion.
Thank you.

shameekv1989
GMATBusters

Official Explanation :



To understand the concept, let us take an example of 2-D Rectangle first:



Attachment:
Sol2.JPG

GMATBusters :-
Let's take the 6 lines as 1st, 2nd, 3rd, 4th, 5th and 6th

When we take \(6_C_2\) -

Let's take 1st and 2nd of each L, W and H - This will form 1*1*1 cube

If we choose 5th and 6th of each L, W, and H - This will also form 1*1*1 cube

Aren't we considering identical cuboids in such case? How are we eliminating identical ones when we take \(6_C_2\)?
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