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Helena invested $8000 in the Tallahassee City Bank at z%

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Senior Manager
Senior Manager
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D
Joined: 02 Jan 2017
Posts: 314
Location: Canada
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Helena invested $8000 in the Tallahassee City Bank at z% [#permalink]

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New post 27 Feb 2017, 07:12
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

91% (01:10) correct 9% (01:30) wrong based on 53 sessions

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Helena invested $8000 in the Tallahassee City Bank at z% simple annual interest for one year with a yield of $450. How much should she invest at s% simple annual interest for one year to yield the same amount?

(1) s/100 = 3/4

(2) s = .4z
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Joined: 05 Mar 2015
Posts: 969
Re: Helena invested $8000 in the Tallahassee City Bank at z% [#permalink]

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New post 27 Feb 2017, 10:34
vikasp99 wrote:
Helena invested $8000 in the Tallahassee City Bank at z% simple annual interest for one year with a yield of $450. How much should she invest at s% simple annual interest for one year to yield the same amount?

(1) s/100 = 3/4

(2) s = .4z



Given 450= 8000z/100-------(a)

find P when 450= Ps/100

(1) s=300/4 thus P can be calculated.......suff
(2) from (a) z can be calculated and thus s can be calculated substituting value z in s = .4z
suff

Ans D
Senior Manager
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Joined: 24 Oct 2016
Posts: 294
Location: India
Concentration: Finance, International Business
Schools: IIMB
GMAT 1: 550 Q42 V28
GPA: 3.96
WE: Human Resources (Retail Banking)
Re: Helena invested $8000 in the Tallahassee City Bank at z% [#permalink]

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New post 08 Mar 2017, 22:22
the answer should be D
we can calculate for Z such as z=450*100/8000=45/8
now statement 1. we can calculate for S too which will be 75, now we need to find the value which has the similar interest =450 , so the 75/100*x=450, equal too 600 so sufficient
statement 2. we can solve for this too so sufficient

hence D
Re: Helena invested $8000 in the Tallahassee City Bank at z%   [#permalink] 08 Mar 2017, 22:22
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Helena invested $8000 in the Tallahassee City Bank at z%

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