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ecorwin
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NextstopISB
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You are right. It would be multiplied by 2.
ecorwin
I was doing this practice problem and came up with a different answer than the one they listed, and I'm just wondering where I went wrong. Here's the problem;
Sixty percent of the 350 students at a high school stated they make calls with their smartphone. Of those who make calls, forty percent also send texts. If two students are selected at random, what is the probability of selecting one student that both makes calls and sends text messages and one student who makes calls but does not send text messages? Give your answer to the nearest whole percent.

I calculated that there is a 0.6 times 0.6 = 0.36 chance of selecting a student who makes calls but doesn't text, and a 0.6 times 0.4 = 0.24 chance of selecting a student who makes calls and texts, so you do 0.36 times 0.24 = 0.0864. I thought that you were supposed to then multiply by 2 since the order here doesn't matter, and you can select the student who calls and texts first or the student who only calls, which would give you a rounded answer of 17 percent but the answer the practice problem gave is 9 percent which leads me to think you don't multiply by 2, but I'm not sure why. If anyone can help I would appreciate it, thanks.
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ecorwin
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Sorry so when you're calculating the total number of ways to select 2 students it would be (350 x 349) / 2 right?