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How many 4-digit number can be made from 2018 with repetition?

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How many 4-digit number can be made from 2018 with repetition? [#permalink]

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New post 28 Dec 2017, 20:43
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

58% (00:42) correct 42% (00:29) wrong based on 32 sessions

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How many 4-digit number can be made from 2018 with repetition?

(A) \(4^4\)
(B) \(4^4-4\)
(C) \(4^4-4^2\)
(D) \(4^4-4^3\)
(E) \(4^3\)


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[Reveal] Spoiler: OA

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How many 4-digit number can be made from 2018 with repetition? [#permalink]

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New post 29 Dec 2017, 02:21
chetan2u wrote:
How many 4-digit number can be made from 2018 with repetition?

(A) \(4^4\)
(B) \(4^4-4\)
(C) \(4^4-4^2\)
(D) \(4^4-4^3\)
(E) \(4^3\)


Let's welcome 2018!!


we have \(4\) digits to choose from. But zero cannot be the first digit. Hence,

1st digit - \(3\) possibilities

Rest of the digits - \(4\) possibilities

\(3 * 4 * 4 * 4\)

\(3 * 4^3\)

\((4-1) * 4^3\)

\(4^4 - 4^3\)

Answer - D

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How many 4-digit number can be made from 2018 with repetition?   [#permalink] 29 Dec 2017, 02:21
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How many 4-digit number can be made from 2018 with repetition?

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