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# How many 4-digit number can be made from 2018 with repetition?

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Math Expert
Joined: 02 Aug 2009
Posts: 5777
How many 4-digit number can be made from 2018 with repetition? [#permalink]

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28 Dec 2017, 20:43
00:00

Difficulty:

55% (hard)

Question Stats:

58% (00:42) correct 42% (00:29) wrong based on 32 sessions

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How many 4-digit number can be made from 2018 with repetition?

(A) $$4^4$$
(B) $$4^4-4$$
(C) $$4^4-4^2$$
(D) $$4^4-4^3$$
(E) $$4^3$$

Let's welcome 2018!!
[Reveal] Spoiler: OA

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How many 4-digit number can be made from 2018 with repetition? [#permalink]

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29 Dec 2017, 02:21
chetan2u wrote:
How many 4-digit number can be made from 2018 with repetition?

(A) $$4^4$$
(B) $$4^4-4$$
(C) $$4^4-4^2$$
(D) $$4^4-4^3$$
(E) $$4^3$$

Let's welcome 2018!!

we have $$4$$ digits to choose from. But zero cannot be the first digit. Hence,

1st digit - $$3$$ possibilities

Rest of the digits - $$4$$ possibilities

$$3 * 4 * 4 * 4$$

$$3 * 4^3$$

$$(4-1) * 4^3$$

$$4^4 - 4^3$$

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How many 4-digit number can be made from 2018 with repetition?   [#permalink] 29 Dec 2017, 02:21
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