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MathRevolution
[GMAT math practice question]

How many 4-digit numbers have only even digits?

A. 500
B. 525
C. 600
D. 625
E. 800

There are FIVE even digits - 0,2,4,6,8.

Let's take 4 digit number as 1000*a + 100*b+10*c+d = abcd.

a - can take 4 values - 2,4,6,8 (Note - If a takes ZERO , the number won't be 4 didgit number)

b,c &d - can take 5 values - 0,2,4,6,8

Total numbers of event digit is - 4*5*5*5 = 4* 125 = 500.

Answer A
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First digit : 2,4,6,8 : 4 Options
Second digit: 0,2,4,6,8 : 5 options
Third digit : 0,2,4,6,8 : 5 options
Fourth digit : 0,2,4,6,8 : 5 options

So we have 4*5*5*5 = 500

Ans: A
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[GMAT math practice question]

How many 4-digit numbers have only even digits?

A. 500
B. 525
C. 600
D. 625
E. 800

There are 5 even digits: 0, 2, 4, 6, 8. In a four-digit number, the first digit cannot be 0, so there are only 4 even numbers available. For the second, third, and fourth digits, there are 5 available numbers. Thus, the number of 4-digit numbers containing only even digits is 4 x 5 x 5 x 5 = 500 numbers.

Answer: A
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=>

Suppoose abcd is 4-digit number with only even digits.
Then a is one of 2, 4, 6 and 8, and b, c and d may be selected from the digits 0, 2, 4, 6 and 8.
So, there are 4 choices for a, and 5 choices for each of b, c and d.

The total number of 4-digit numbers with only even digits is thus 4*5*5*5 = 500.

Therefore, A is the answer.
Answer: A
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