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Bunuel
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How many digits are in (8×10^14)(10×10^10)? 26 Apr 2016, 00:53
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

25% (medium)

Question Stats:

70% (00:49) correct 30% (01:05) wrong based on 520 sessions

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How many digits are in (8×10^14)(10×10^10)?

A. 24
B. 25
C. 26
D. 27
E. 28
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C
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raarun
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How many digits are in (8×10^14)(10×10^10)? 26 Apr 2016, 06:41
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The question simplfies to (8×10^14)(10^11)
=> 8*10^25
=> Will contain 25 zeros +1 digit 8
=>26

Ans C
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How many digits are in (8×10^14)(10×10^10)? 30 Dec 2017, 23:21
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Bunuel
How many digits are in (8×10^14)(10×10^10)?

A. 24
B. 25
C. 26
D. 27
E. 28
Show more

Bunuel can you help me in this. Though I know the concept, still I am counting it as 27.

(8×10^14) ; 10^14 means fourteen "0s" and one "1" So total 15 digits ; 8 does not change the number of digits

(10×10^10) ; 10^11 means 12 digits

So 15+12 = 27
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How many digits are in (8×10^14)(10×10^10)? 30 Dec 2017, 23:30
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Bunuel
How many digits are in (8×10^14)(10×10^10)?

A. 24
B. 25
C. 26
D. 27
E. 28

Bunuel can you help me in this. Though I know the concept, still I am counting it as 27.

(8×10^14) ; 10^14 means fourteen "0s" and one "1" So total 15 digits ; 8 does not change the number of digits

(10×10^10) ; 10^11 means 12 digits

So 15+12 = 27
Show more

You cannot add like that. For example, 10 has 2 digits but 10*10 does not have 2 + 2 = 4 digits it has 3 digits.

You should do the following way: (8×10^14)(10×10^10) = 8*10^25 --> 10^25 has 26 digits. Multiplying it by 8 does not change the number of digits.

Answer: C.
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How many digits are in (8×10^14)(10×10^10)? 30 Dec 2017, 23:39
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Bunuel
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How many digits are in (8×10^14)(10×10^10)?

A. 24
B. 25
C. 26
D. 27
E. 28

Bunuel can you help me in this. Though I know the concept, still I am counting it as 27.

(8×10^14) ; 10^14 means fourteen "0s" and one "1" So total 15 digits ; 8 does not change the number of digits

(10×10^10) ; 10^11 means 12 digits

So 15+12 = 27

You cannot add like that. For example, 10 has 2 digits but 10*10 does not have 2 + 2 = 4 digits it has 3 digits.

You should do the following way: (8×10^14)(10×10^10) = 8*10^25 --> 10^25 has 26 digits. Multiplying it by 8 does not change the number of digits.

Answer: C.
Show more

Can we deduce that number less than 10 does not change the number of digits ever?
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How many digits are in (8×10^14)(10×10^10)? 30 Dec 2017, 23:47
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Bunuel can you help me in this. Though I know the concept, still I am counting it as 27.

(8×10^14) ; 10^14 means fourteen "0s" and one "1" So total 15 digits ; 8 does not change the number of digits

(10×10^10) ; 10^11 means 12 digits

So 15+12 = 27

You cannot add like that. For example, 10 has 2 digits but 10*10 does not have 2 + 2 = 4 digits it has 3 digits.

You should do the following way: (8×10^14)(10×10^10) = 8*10^25 --> 10^25 has 26 digits. Multiplying it by 8 does not change the number of digits.

Answer: C.

Can we deduce that number less than 10 does not change the number of digits ever?
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It won't if you have a*10^n, where a is a single digit integer. But for other cases it might not be true. For example, 3*400.
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How many digits are in (8×10^14)(10×10^10)? 30 Dec 2017, 23:56
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Bunuel
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How many digits are in (8×10^14)(10×10^10)?

A. 24
B. 25
C. 26
D. 27
E. 28

Bunuel can you help me in this. Though I know the concept, still I am counting it as 27.

(8×10^14) ; 10^14 means fourteen "0s" and one "1" So total 15 digits ; 8 does not change the number of digits

(10×10^10) ; 10^11 means 12 digits

So 15+12 = 27

You cannot add like that. For example, 10 has 2 digits but 10*10 does not have 2 + 2 = 4 digits it has 3 digits.

You should do the following way: (8×10^14)(10×10^10) = 8*10^25 --> 10^25 has 26 digits. Multiplying it by 8 does not change the number of digits.

Answer: C.

Can we deduce that number less than 10 does not change the number of digits ever?
Show more


Hi..
You can't take that as a rule..
It depends on other factors too..
8*10^2.... 8 will not effect
8*20^2.... 8 will effect...

Why you have gone wrong is that you have separated the 10s..
(8*10^14)(10*10^11)....
Although you have correctly solved 10*10^11, you have added an extra digit of 1 from 10^14..
10*10^11 could have meant 10 - 2 digits and 10^10- 10 zeroesand 1 digit for '1', so 10+1=11 digits
Total 2+11=13digits.. but is it so ...NO
It is 12 digits because 10*10^10=10^11, meaning 12 digits
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How many digits are in (8×10^14)(10×10^10)? 30 Mar 2023, 04:54
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We have \((8*10^{14})(10*10^{10})\)

Since it is all multiplication, we can rearrange the terms as follows

\((8*10^{14}*10^1*10^{10})\)

which gives us

\(8*10^{25}\)

\(10^{25}\) gives us \(1\) followed by \(25\) zeroes or in total \(26\) digits.

Multiplying this by \(8\) does not change the number of digits.

Answer is Choice C
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How many digits are in (8×10^14)(10×10^10)? 17 Feb 2025, 12:20
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