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Bunuel
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How many factors does 36^2 have?
A 2
B 8
C 24
D 25
E 26
Please help as to how to solve this problem with 1 minute !!

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Back to the original question:

How many factors does 36^2 have?

\(36^2=(2^2*3^2)^2=2^4*3^4\) --> # of factors \((4+1)*(4+1)=25\).

Answer: D.

Or another way: 36^2 is a perfect square, # of factors of perfect square is always odd (as perfect square has even powers of its primes and when adding 1 to each and multiplying them as in above formula you'll get the multiplication of odd numbers which is odd). Only odd answer in answer choices is 25.

Hope it helps.


Thanks a ton !!.. loved the approach !
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Factors of a perfect square can be derived by using prime factorization and then using the formula to find perfect square's factors.

In this case \((36)^2= (2^2*3^2)^2=2^4*3^4\) or \((36)^2=(6^2)^2=(6)^4=(2*3)^4=2^4*3^4\)

And now you can use the formula explained above by Bunuel to determine the answer, which is \((4+1)*(4+1)=5*5=25=Odd\)(Trick is there must be odd number of factors of a perfect square and only 25 is odd in answer choices, so it can be solved within 30 seconds or less :) )

Please! go through the GMAT Math Book by GMAT CLUB (written by bunuel & walker), all of these tips & tricks are written there. (even I have compiled them in one .pdf file and is shared here on Math forum)
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This method is worth bookmarking. Appreciate it
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Bunuel
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How many factors does 36^2 have?

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.


Hi Bunuel, can you please clarify when we count multiplies of 1? When do we need to use (1+1)(4+1)(4+1) applicable to this question.
Thanks
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Bunuel
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How many factors does 36^2 have?

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.


Hi Bunuel, can you please clarify when we count multiplies of 1? When do we need to use (1+1)(4+1)(4+1) applicable to this question.
Thanks

Don't understand your question. Can you please elaborate?
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fukirua
Bunuel


Don't understand your question. Can you please elaborate?

I mean 36^2=(2^4)*(3^4), the number of factors is (4+1)(4+1)=25 - this is clear.
However 36^2 could be (1^1)(2^4)(3^4), which comes to (1+1)(4+1)(4+1)=50. In which cases in GMAT should I count the powers of 1, which doubles the number of factors?
Thank you

Understood now. The answer is never.

To find the number of factors of a positive integers we should make its prime factorization. Now, 1 is not a prime, thus you shouldn't write it when making prime factorization of an integer.

Hope it's clear.
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I remember reading a rule in MGMAT that any perfect square will have an odd number of factors. 25 is the only odd answer choice. Is that right?
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I remember reading a rule in MGMAT that any perfect square will have an odd number of factors. 25 is the only odd answer choice. Is that right?

Yes, it is. Check my solution here: how-many-factors-does-36-2-have-126422.html#p1032696

Tips about positive perfect squares:

1. The number of distinct factors of a perfect square is ALWAYS ODD. The reverse is also true: if a number has the odd number of distinct factors then it's a perfect square;

2. The sum of distinct factors of a perfect square is ALWAYS ODD. The reverse is NOT always true: a number may have the odd sum of its distinct factors and not be a perfect square. For example: 2, 8, 18 or 50;

3. A perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of Even-factors. The reverse is also true: if a number has an ODD number of Odd-factors, and EVEN number of Even-factors then it's a perfect square. For example: odd factors of 36 are 1, 3 and 9 (3 odd factor) and even factors are 2, 4, 6, 12, 18 and 36 (6 even factors);

4. Perfect square always has even powers of its prime factors. The reverse is also true: if a number has even powers of its prime factors then it's a perfect square. For example: \(36=2^2*3^2\), powers of prime factors 2 and 3 are even.

Hope this helps.
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enigma123
How many factors does 36^2 have?

A. 2
B. 8
C. 24
D. 25
E. 26

We can use the rule of adding 1 to each exponent of each unique prime and then multiplying our values together:

36^2 = (9 x 4)^2 = (3^2 x 2^2)^2 = 3^4 x 2^4

(4 + 1)(4 + 1) = 5 x 5 = 25

Alternate solution:

An interesting fact about perfect squares greater than 1 is that they always have an odd number of factors. For example, the factors of 4 are 1, 2, and 4 (a total of 3 factors) and the factors of 100 are 1, 2, 5, 10, 20, 50, and 100 (a total of 7 factors). Since 36^2 is a perfect square, it should have an odd number of factors. The only odd number in the answer choices is 25.

Answer: D
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Quote:


Tips about the perfect square:
1. The number of distinct factors of a perfect square is ALWAYS ODD.
2. The sum of distinct factors of a perfect square is ALWAYS ODD.
3. A perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of Even-factors.
4. Perfect square always has even powers of its prime factors.

Hope it helps.


Hello niks18, could you please advice regarding Bunuel`s tips about the perfect square. please see below and advice what i missed or did wrong, or counted incorrectly :) many thanks!

lets take 36. here is prime factorization of 36 (2*18) ---> (18) ---> (2*9) ---> (9) --->(3*3)

\(Tips about the perfect square\)

1. The number of distinct factors of a perfect square is ALWAYS ODD. lets take 36 in all cases to test your tips:) - it has 1, 2, 3, 9 = 4 as distinct factors, no but it is EVEN :?

2. The sum of distinct factors of a perfect square is ALWAYS ODD. 36 - so it has 1, 2, 3, 9 as distinct factors hence 1+ 2+3+9 = 15 is it correct ?

3. A perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of Even-factors. let me break down this sentence into two clauses:)

A perfect square ALWAYS has an ODD number of Odd-factors ---> odd numbers are 1, 3, 9 so total 3 odd numbers

A perfect square ALWAYS has an EVEN number of Even-factors ---> 2, 8 so in total 2 numbers is corrrect :? but how about 6 ! ?? or is my prime factorization incorrect ??

4. Perfect square always has [b]even powers of its prime factors
. ---> so \(36\) = \(2^2\) and \(3^2\)
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Quote:


Tips about the perfect square:
1. The number of distinct factors of a perfect square is ALWAYS ODD.
2. The sum of distinct factors of a perfect square is ALWAYS ODD.
3. A perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of Even-factors.
4. Perfect square always has even powers of its prime factors.

Hope it helps.


Hello niks18, could you please advice regarding Bunuel`s tips about the perfect square. please see below and advice what i missed or did wrong, or counted incorrectly :) many thanks!

lets take 36. here is prime factorization of 36 (2*18) ---> (18) ---> (2*9) ---> (9) --->(3*3)

\(Tips about the perfect square\)

1. The number of distinct factors of a perfect square is ALWAYS ODD. lets take 36 in all cases to test your tips:) - it has 1, 2, 3, 9 = 4 as distinct factors, no but it is EVEN :?

2. The sum of distinct factors of a perfect square is ALWAYS ODD. 36 - so it has 1, 2, 3, 9 as distinct factors hence 1+ 2+3+9 = 15 is it correct ?

3. A perfect square ALWAYS has an ODD number of Odd-factors, and EVEN number of Even-factors. let me break down this sentence into two clauses:)

A perfect square ALWAYS has an ODD number of Odd-factors ---> odd numbers are 1, 3, 9 so total 3 odd numbers

A perfect square ALWAYS has an EVEN number of Even-factors ---> 2, 8 so in total 2 numbers is corrrect :? but how about 6 ! ?? or is my prime factorization incorrect ??

4. Perfect square always has [b]even powers of its prime factors
. ---> so \(36\) = \(2^2\) and \(3^2\)

Hi dave13

you have factorized 36 incorrectly.

\(36=2^2*3^2\). Hence number of factors \(= (2+1)*(2+1)=9=Odd\)

Factors of 36 are 1,2,3,4,6,9,12,18 & 36. Now figure out the validity of tips yourself.
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praveengmat
How many factors does 36^2 have?

A. 2
B. 8
C. 24
D. 25
E. 26

factors of 36 ; 2^2*3^2 = 9
so for 36^2 ; (2^2)^2*(3^2)^2 ; 2^4*3^4 ; 25
IMO D;
also another key take away perfect square have odd factors so out of given option only D is valid
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Question seen in Manhattan GMAT test
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praveengmat
How many factors does 36^2 have?

A. 2
B. 8
C. 24
D. 25
E. 26
\(36^2 = 6^4 = 2^4*3^4\)

Thus, no of factors must be \((4+1)(4+1) = 25\), Answer must be (D)
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Bunuel
praveengmat
How many factors does 36^2 have?
A 2
B 8
C 24
D 25
E 26
Please help as to how to solve this problem with 1 minute !!

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Back to the original question:

How many factors does 36^2 have?

\(36^2=(2^2*3^2)^2=2^4*3^4\) --> # of factors \((4+1)*(4+1)=25\).

Answer: D.

Or another way: 36^2 is a perfect square, # of factors of perfect square is always odd (as perfect square has even powers of its primes and when adding 1 to each and multiplying them as in above formula you'll get the multiplication of odd numbers which is odd). Only odd answer in answer choices is 25.

Hope it helps.


At first I thought the result should be 1296. But thanks to your explanation, I understand better why 25 comes out. Mathematics is truly magical, isn't it?
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