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Bunuel
How many factors of the number \(2^6*3^5*5^4*6^3\) are multiples of 360?

A. 36
B. 108
C. 144
D. 196
E. 288


Are You Up For the Challenge: 700 Level Questions

Any multiple of 360 can be written as 360*k, where k is an integer.

On prime factorizing 360, we get = \(2^3 *3^2 * 5^1\)

So, we can write the given number \(2^6*3^5*5^4*6^3\) as : \((2^3 * 3^2 * 5^1) * (2^6 * 3^6 * 5^3) = 360* (2^6 * 3^6 * 5^3)\)

Now, we just need to find the total number of factors of \((2^6 * 3^6 * 5^3)\). Because all the factors when multiplied with 360 will all be multiples of 360. :)

Total factors of \([2^6 * 3^6 * 5^3]\)

\(= (6 + 1) (6 + 1) (3 + 1)\)

\(= 7 * 7 * 4\)

\(= 196\)

Correct answer is Option D.
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360= 2^3*3^2*5
to determine factors of \(2^6*3^5*5^4*6^3\) which are multiple of 360 ;
\(2^6*3^5*5^4*6^3\) /2^3*3^2*5 = 2^6*3^6*5^3 ; 7*7*4 ; 196
IMO D

Bunuel
How many factors of the number \(2^6*3^5*5^4*6^3\) are multiples of 360?

A. 36
B. 108
C. 144
D. 196
E. 288


Are You Up For the Challenge: 700 Level Questions
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Bunuel
How many factors of the number \(2^6*3^5*5^4*6^3\) are multiples of 360?

A. 36
B. 108
C. 144
D. 196
E. 288


Are You Up For the Challenge: 700 Level Questions

Breaking the given factors down further, we have:

2^6 x 3^5 x 5^4 x 2^3 x 3^3

2^9 x 3^8 x 5^4

and

360 = 36 x 10 = 6 x 6 x 2 x 5 = 2^3 x 3^2 x 5^1

Since (2^9 x 3^8 x 5^4)/(2^3 x 3^2 x 5^1) = 2^6 x 3^6 x 5^3, there are (6 + 1) (6 + 1) (3 + 1) = 7 x 7 x 4 = 196 multiples of 360.

Answer: D
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