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How many five-digit positive integers can be formed by using digits

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mastergrinder
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How many five-digit positive integers can be formed by using digits [#permalink] New post   05 Nov 2023, 05:01
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How many five-digit positive integers can be formed by using digits 1, 2, and 4 if the digit 1 is used once and each of the digits 2 and 4 are used twice?

A. 20
B. 25
C. 30
D. 45
E. 60
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chetan2u
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Re: How many five-digit positive integers can be formed by using digits [#permalink] New post   05 Nov 2023, 05:44
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mastergrinder wrote:
How many five-digit positive integers can be formed by using digits 1, 2, and 4 if the digit 1 is used once and each of the digits 2 and 4 are used twice?

A. 20
B. 25
C. 30
D. 45
E. 60


Please change tag. It is not a probability question.

So we have to make 5-digit number from 1,2,2,4,4
Straight formula \(\frac{5!}{2!2!}\) or 30
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Re: How many five-digit positive integers can be formed by using digits [#permalink] New post   06 Nov 2023, 09:12
Agree, use formula 5!/(2!2!).

5! is the permutation of 5 unique items A, B, C, D, E.

Divide by 2! and 2! for repitition of '2' and '4' in the question.
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Re: How many five-digit positive integers can be formed by using digits [#permalink] New post   06 Nov 2023, 13:05
Total ways possible will be
5!/(2!*2!)=30

mastergrinder wrote:
How many five-digit positive integers can be formed by using digits 1, 2, and 4 if the digit 1 is used once and each of the digits 2 and 4 are used twice?

A. 20
B. 25
C. 30
D. 45
E. 60


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Re: How many five-digit positive integers can be formed by using digits [#permalink]
06 Nov 2023, 13:05
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