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05 Nov 2023, 05:01
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Difficulty:
35%
(medium)
Question Stats:
73% (01:19) correct
27%
(02:03)
wrong
based on 86
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How many five-digit positive integers can be formed by using digits 1, 2, and 4 if the digit 1 is used once and each of the digits 2 and 4 are used twice?
A. 20
B. 25
C. 30
D. 45
E. 60
A. 20
B. 25
C. 30
D. 45
E. 60
05 Nov 2023, 05:44
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mastergrinder
How many five-digit positive integers can be formed by using digits 1, 2, and 4 if the digit 1 is used once and each of the digits 2 and 4 are used twice?
A. 20
B. 25
C. 30
D. 45
E. 60
A. 20
B. 25
C. 30
D. 45
E. 60
Please change tag. It is not a probability question.
So we have to make 5-digit number from 1,2,2,4,4
Straight formula \(\frac{5!}{2!2!}\) or 30
ankitmba95
Joined: 31 Oct 2023
Last visit: 17 Dec 2023
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Concentration: Finance, Technology
Schools: Columbia CBS'26 Booth '26 Kellogg '26 Stern '26 (S)
GMAT 1: 710 Q50 V35
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Schools: Columbia CBS'26 Booth '26 Kellogg '26 Stern '26 (S)
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06 Nov 2023, 09:12
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Agree, use formula 5!/(2!2!).
5! is the permutation of 5 unique items A, B, C, D, E.
Divide by 2! and 2! for repitition of '2' and '4' in the question.
5! is the permutation of 5 unique items A, B, C, D, E.
Divide by 2! and 2! for repitition of '2' and '4' in the question.
