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13 Aug 2025, 22:00
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C
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Difficulty:
15%
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Question Stats:
72% (00:43) correct
28%
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wrong
based on 160
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How many integer values are there for x such that 0 < 4x + 8 < 12?
A. 0
B. 1
C. 2
D. 3
E. 4
A. 0
B. 1
C. 2
D. 3
E. 4
13 Aug 2025, 22:23
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0<4x+8 => -2<x
Also 4x+8<12
=> x<1
So -2<x<1
Thus x belongs to {-1,0}
Hence 2 integers
Answer is C
Also 4x+8<12
=> x<1
So -2<x<1
Thus x belongs to {-1,0}
Hence 2 integers
Answer is C
Bunuel
14 Aug 2025, 20:30
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4x+8<12
4x<4
x<1
from the other half
4x+8>0
4x>-8
x>-2
hence the values that x can take are -1, 0
hence 2 option C
4x<4
x<1
from the other half
4x+8>0
4x>-8
x>-2
hence the values that x can take are -1, 0
hence 2 option C
Bunuel
