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24 Jan 2022, 04:45
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Difficulty:
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56% (02:38) correct
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How many integers between 3000 and 4000 that have distinct digits and increase from left to right ?
(A) 20
(B) 48
(C) 60
(D) 120
(E) 600
Are You Up For the Challenge: 700 Level Questions
(A) 20
(B) 48
(C) 60
(D) 120
(E) 600
Are You Up For the Challenge: 700 Level Questions
24 Jan 2022, 07:41
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The four digit number will have to start with 3, which means that the only numbers that need to be considered here are 4, 5, 6, 7, 8 and 9.
We are looking for how many combinations of 3 can be made with these 6 numbers. While order does matter here, we need not take it into account while working out the question. This is as every possible combination of 3 numbers will have one way in which the numbers will ascend from left to right.
\(\frac{6!}{3!3!} = 20\)
Answer A.
We are looking for how many combinations of 3 can be made with these 6 numbers. While order does matter here, we need not take it into account while working out the question. This is as every possible combination of 3 numbers will have one way in which the numbers will ascend from left to right.
\(\frac{6!}{3!3!} = 20\)
Answer A.
