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31 Dec 2019, 03:15
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E
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How many litres of solutions having 30% milk and 70% milk should be mixed so that we get 40 litres of 45% milk solution?
A. 10, 30
B. 12, 28
C. 15, 25
D. 20, 20
E. 25, 15
A. 10, 30
B. 12, 28
C. 15, 25
D. 20, 20
E. 25, 15
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01 Jan 2020, 03:06
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\(\frac{W_a}{W_b} = \frac{Avg_b-Avg_{overall}}{Avg_{overall}-Avg_a}\)
\(\frac{W_a}{W_b} = \frac{70-45}{45-30} = \frac{25}{15}\)
Answer is (E)
\(\frac{W_a}{W_b} = \frac{70-45}{45-30} = \frac{25}{15}\)
Answer is (E)
30 Nov 2024, 15:25
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Let's assume the weight of Solution A to be - A
And it's mentioned that the final solution has A and B and together they make 40 litres.
So, weight of B would be = 40-A
Let's create a table to help us with visualisation
Now let's create the final equation:
30% of A + 70% of B = % and litres of the final solution
.30(A) + .70(40-A) = .45*40
A = 25
So, weight of A= 25 litres
And weight of B = 40-A i.e. 40-25 = 15 litres
Correct answer 25,15
And it's mentioned that the final solution has A and B and together they make 40 litres.
So, weight of B would be = 40-A
Let's create a table to help us with visualisation
| Content | % Milk | Litres | Total |
|---|---|---|---|
| A | 30% | A | 30% of A |
| B | 70% | 40 - A | 70% of (40 - A) |
| Final Mixture | 45% | 40 | 45% of 40 |
Now let's create the final equation:
30% of A + 70% of B = % and litres of the final solution
.30(A) + .70(40-A) = .45*40
A = 25
So, weight of A= 25 litres
And weight of B = 40-A i.e. 40-25 = 15 litres
Correct answer 25,15
