LevanKhukhunashvili
Mohammadmo
200÷12=~16
200÷13=~15
200÷156=~1
15+16-1=30
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Sir
chetan2u is that correct approach above?
I have done tremendous calculations to reach those 15 and 16
\(\frac{(195-13)}{13}+1=15\)
\(\frac{(192-12)}{12}+1=16\)
Wasted precious time

Regards
L
Hi,
the sign ~ is NOT correct..\(200/13 = 15\frac{5}{13}\).....So, you take only the integer 15...
\(\frac{200}{12}=16\frac{8}{12}\). Here it is ~17, but you will take 16, as the integer portion is 16 and there are 16 multiples of 12
The above lists consists of repetition of common multiples of 12 and 13, so remove them..
LCM(12,13)=156
\(\frac{200}{156}=1\frac{44}{156}\)...so 1
answer = 15+16-1=30
Quote:
\(\frac{(195-13)}{13}+1=15\)
Where you would do this..
If the set of number does NOT begin from 1...for example - Number of multiples of 12 from 100 to 200
But here we were looking for multiples in first 200 numbers...