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Russ19
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Any 2 digit number with ten's digit x and one's digit y can be written in form 10x+y.
So,
Actual number: 10x+y;
After digit reversal:10y+x

According to given condition
\(10y+x -(10x+y) = 9\)
\(9y-9x=9\)
\(y-x=1\)
\(y=x+1;\)

to satisfy this x can only range from 1 to 8 inclusive;

Hence Answer: 8
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the numbers are:

12
23
34
45
56
67
78
89

the pattern is easy to spot, the tens digit is 1 less than the unit digit

Answer: C
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I spotted a pattern and did what Anirudhas did

12 -- 21
23 --- 32
34 --- 43

This pattern can be continued through 8, and it would reverse once you get to 9.

The problem took me a bit too long for how easy the pattern was, took a bit over 2 mins for me to solve.
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Can anyone tell me why the answer is not 9?

10
21
32
43
54
65
76
87
98
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JeremySkidmore29
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gagankhanna08
Can anyone tell me why the answer is not 9?

10
21
32
43
54
65
76
87
98

The number has to increase by 9. So 98 would be 89 which would be a decrease.

Reread the question slowly. This happens to me a lot and is so aggravating lol
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gagankhanna08
Can anyone tell me why the answer is not 9?

10
21
32
43
54
65
76
87
98
Please read the question carefully. It says when you increase the said number by 9 its digits are reversed.

10+9=19 now is the digits reversed? NO
21+9=30, are the digits reversed? Again no
The pattern is 12, 23, 34 ....
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gagankhanna08
Can anyone tell me why the answer is not 9?

10
21
32
43
54
65
76
87
98

@gagankanna08 .Question says when you reverse the digits, numbers should increase by 9

but the numbers you are listing gets decreased when digits are reversed.
So the correct list would be 12,23,34........
01 wont be in the list as it is not a 2 digit number.
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rocky620
The answer should be 10

23,32, 34,43, 45,54, 67,76, 89,98

hi rocky620!

just put it this way:

12 => 21 = 1
23 => 32 = 2
34 => 43 = 3
45 => 54 = 4
56 => 65 = 5
67 => 76 = 6
78 => 87 = 7
89 => 98 = 8

Tot= 8

Hope this helps!
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