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How many two digit numbers of distinct digits can be formed by us [#permalink]
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Updated on: 04 Aug 2015, 04:48
Question Stats:
73% (01:44) correct 27% (01:18) wrong based on 212 sessions
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Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 14 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :)
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Originally posted by GMATinsight on 04 Aug 2015, 02:56.
Last edited by GMATinsight on 04 Aug 2015, 04:48, edited 2 times in total.



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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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04 Aug 2015, 04:32
GMATinsight wrote: Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 13 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :) GMATinsight, I am getting 14 possible cases 12 15 21 24 27 36 42 45 51 54 57 63 72 75



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How many two digit numbers of distinct digits can be formed by us [#permalink]
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04 Aug 2015, 04:50
Engr2012 wrote: GMATinsight wrote: Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 13 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :) GMATinsight, I am getting 14 possible cases 12 15 21 24 27 36 42 45 51 54 57 63 72 75 Thank you. Type error. Have corrected. There are basically 7 cases {12, 15, 24, 27, 36, 45, 57} in forward order and 7 cases after reversing the digits so a total of 14 cases. Thanks. P.S. I mentioned Q# in Subject line intentionally so that reader can differentiate among the different questions with similar starting languageSo I would still encourage to mention the same however being a moderator you can take a stand to not to deviate from the rules.
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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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05 Aug 2015, 11:27
GMATinsight wrote: Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 14 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :) ALTERNATECONCEPT: A number will be divisible by 3 if sum of all the digits of the number is divisible by 3Here the Possible sum of the two distinct digits can be 3, 6, 9 and 12 only in order to satisfy the given condition If sum of Digits = 3, No. = 12, 21  2 Cases If sum of Digits = 6, No. = 15, 24, 42, 51  4 Cases If sum of Digits = 9, No. = 27, 36, 45, 54, 63, 72  6 Cases If sum of Digits = 12, No. = 57, 75  2 Cases Total Cases = 2+4+6+2 = 14 cases Answer: option E
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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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05 Aug 2015, 11:36
GMATinsight wrote: Engr2012 wrote: GMATinsight wrote: Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 13 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :) GMATinsight, I am getting 14 possible cases 12 15 21 24 27 36 42 45 51 54 57 63 72 75 Thank you. Type error. Have corrected. There are basically 7 cases {12, 15, 24, 27, 36, 45, 57} in forward order and 7 cases after reversing the digits so a total of 14 cases. Thanks. P.S. I mentioned Q# in Subject line intentionally so that reader can differentiate among the different questions with similar starting languageSo I would still encourage to mention the same however being a moderator you can take a stand to not to deviate from the rules. GMATinsight, I completely understand your concern but these rules were made by Bunuel and thus dont want to deviate from them. One way to go around this rule is to rephrase these questions as: How many two digit numbers divisble by 3 can be formed by using digits 1, 2, 3, 4, 5, 6 and 7? or Using digits 1, 2, 3, 4, 5, 6 and 7 how many 2 digit numbers can be formed such that the numbers are divisible by 3? etc.



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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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05 Aug 2015, 11:52
GMATinsight wrote: Q2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? A) 9 B) 10 C) 11 D) 12 E) 14 Source : http://www.GMATinsight.comGood Questions also deserve Kudos :) In this case, it probably fastest, just to write out the numbers that satisfy the criteria: 10's  12, 15 20's  21, 24, 27 30's  36 (33 does not satisfy the "disticnt digit" criteria) 40's  42, 45 50's  51, 54, 57 60's  63 (66 does not satisfy the "distinct digit" criteria) 70's  72, 75 Correct answer is E) 14
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How many two digit numbers of distinct digits can be formed by us [#permalink]
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19 Aug 2016, 15:15
there are 7*6=42 possible distinct two digit combinations 42/3=14 14



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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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07 Sep 2016, 08:22
is there a way to get to the answer without actually counting all the possibilities? i got: 12 and 21 15 and 51 24 and 42 27 and 72 36 and 63 45 and 54 57 and 75
7 pairs  14 numbers...



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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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07 Sep 2016, 13:07
7/9*6/10*1/3*90=14



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How many two digit numbers of distinct digits can be formed by us [#permalink]
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07 Sep 2016, 22:56
One can also apply , taking X & Y. X+Y = 3,6,9,12...and so on
where X & Y belongs to (1,2,3,4,5,6,7)
greatest number formed to be divisible by 3 = 75==> 7+5 =12
1. X+ Y = 3 (12,21) 2. X+Y = 6 (24,42,15,51) 3. X+Y = 9 (27,72,36,63,45,54) 4 X+Y =12 (57,75)
Total = 14 pairs
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Re: How many two digit numbers of distinct digits can be formed by us [#permalink]
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