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Hi gmatophobia

Needed your help in understanding this concept

https://www.manhattanprep.com/gmat/blog ... tive%20one.

So I read this article on how to deal with square roots in gmat. It says that we do not consider negative values after square root

Why is -(3)^1/2 correct?

Doesn't this question yield only one positive root?
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Jayam12
Hi gmatophobia

Needed your help in understanding this concept

https://www.manhattanprep.com/gmat/blog ... tive%20one.

So I read this article on how to deal with square roots in gmat. It says that we do not consider negative values after square root

Why is -(3)^1/2 correct?

Doesn't this question yield only one positive root?
Check the highlighted part below.

­Mathematically, \(\sqrt{...}\) is the square root sign, a function (called the principal square root function), which cannot give negative result. So, this sign (\(\sqrt{...}\)) always means non-negative square root.


The graph of the function f(x) = √x

Notice that it's defined for non-negative numbers and is producing non-negative results.

TO SUMMARIZE:
When the GMAT (and generally in math) provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the non-negative root. That is:

√9 = 3, NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;

Notice that in contrast, the equation x^2 = 9 has TWO solutions, +3 and -3. Because x^2 = 9 means that x =-√9 =-3 or x = √9 = 3.

Hope it helps.
 ­
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­1/x * ( 1/(x+1)  +  1/(x+2) ) = 1/(x+1)
1/x+1  +  1/x+2 = x/x+1
Simplify,
(x+2+x+1) / (x+1)*(x+2)  = x / x+1
2x+3 / x+2 = x
2x+3 = x^2 + 2x
cancel out 2x
x^2 = 3
take square root 
2 values possible answer C.
 
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If someone solved it the way I did, either they will cut two x's or they will not cut anything solve as it is in which case x=0 could also be a solution but notice that x can't be 0 as then 1/0 will be formed in the original eqn which mathematically isn't correct, hence only 2 solutions.

But if you cut x with each other it is correct for this question as it is an equality and not an inequality so you don't need to worry about the sign, second looking at the denominator we can tell x is not 0 so you can actually cancel the x's which each other and still get the right solution of 2 solutions.

I was confused between 2 & 3 when i face this question in a mock test, so putting this out there for anyone who chose 3 instead of 2, as they found x=0 also a solution when they solved the equation.
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Bunuel, KarishmaB

Is there a faster way to solve this?
It took me ~3.5 minutes because at first glance it looks like I need to take the LCM and expand into a cubic. Only later I noticed the (x + 1) common factor, which reduces it to a quadratic.

But is there a shortcut or a recognition trick so that I don’t start expanding into a cubic in the first place? Any conceptual way to see the simplification earlier, instead of solving everything algebraically?

Looking for a more efficient GMAT-style approach.

Thanks!
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Good one, this makes more sense.

Thinking in direction that.. we see common terms in denominators , so just need to find suitable multiplication, this helps solve this questions really fast in like 20-25 seconds.
HarshavardhanR


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can anyone share more such question of these types, it would be very helpful. thank you in advance.
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why can't x be 0,-1,-2
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why can't x be 0,-1,-2
Because for x = 0, -1, or -2, the denominators become zero, so the equation is not defined. Remember, division by 0 is not allowed.
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