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Bunuel
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Bunuel
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Bunuel
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I think this is a high-quality question and I agree with explanation.
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k11work
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90+50+40 = 180 = Ex1 + 2Ex2 + 3Ex3
since Ex2 = 70,
40 = Ex1 + 3Ex3 ..... (i)

also,
150 = Ex1 + Ex2 + Ex3 + None
using (i), Ex1 + Ex3 = 40 - 2Ex3
150 = 70 + 40 - 2Ex3 + None
None = 40 + 2Ex3 ..... (ii)

From i and options given, we can see that Ex3 will be 10 at max.
if Ex3 can be 10 max then using ii , None can be 60 at max.

Ans : 60, 10
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I like the solution - it’s helpful.
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