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Bunuel
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Limit should start from 796 I guess. Why 795?

795 is 3rd value then there will be no pending.

Max should be 16 only.

Please guide
It must start at 795 because when RT = 795, exactly 4 days are above it (810, 820, 823, 830). That satisfies the condition, so 795 is already valid as the lower limit.
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I did this way - let me know Bunuel if this is correct
Arrange in ascending 780, 790,795, 810, 820, 823, 830
for max take highest 4 nos 810, 820, 823, 830 - So 1 is not answered fully let that be 830 - threshold is 829
For min take least 4 nos 780, 790,795, 810 - similar thinking threshold is 809
Now Min max from 812
Min 812-809=3
Max 829-812=17
Still this took me 2.5 mins :( Your solution confused me
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I did not quite understand the solution. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests.? whats the use of this i 1st was considering 17 and 3 but this statement confused me and i marked 16 and 2
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I did not quite understand the solution. If the number of requests on a given day exceeds the RT, the site processes only the first RT requests.? whats the use of this i 1st was considering 17 and 3 but this statement confused me and i marked 16 and 2
That line only tells you how many are discarded when requests exceed RT:

unaddressed = total requests - RT.

You can check alternative solutions here: https://gmatclub.com/forum/gmat-club-ol ... 47485.html
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