sjuniv32
If \((\sqrt{0.000125} + 0.005)(\sqrt{0.25x} - 0.5) = 0.01\), what is the value of x?
(A) 0.0125
(B) 0.125
(C) 0.25
(D) 1.25
(E) 5
One should realize from the terms that we may be looking at \((a+b)(a-b)=a^2-b^2\)
\((\sqrt{0.000125} + 0.005)(\sqrt{0.25x} - 0.5) = 0.01\)
Multiply both sides by 100,
\(100*(\sqrt{0.000125} + 0.005)(\sqrt{0.25x} - 0.5) =100* 0.01=1\)
\((\sqrt{100^2*0.000125} + 100*0.005)(\sqrt{0.25x} - 0.5) = 1\)
\((\sqrt{1.25} + 0.5)(\sqrt{0.25x} - 0.5) = 1\)
Multiply both sides by \(\sqrt{1.25}-0.5\)
\((\sqrt{1.25}-0.5)(\sqrt{1.25} + 0.5)(\sqrt{0.25x} - 0.5) = 1*(\sqrt{1.25}-0.5)\)
\((\sqrt{1.25}^2-0.5^2)(\sqrt{0.25x} - 0.5) = (\sqrt{1.25}-0.5)\)
\((1.25-0.25)(\sqrt{0.25x} - 0.5) = (\sqrt{1.25}-0.5)\)
\((1)(\sqrt{0.25x} - 0.5) = (\sqrt{1.25}-0.5)\)
\((1)(\sqrt{0.25x} ) = (\sqrt{1.25})\)
Square both sides
\(0.25x=1.25\)
\(x=\frac{1.25}{0.25}=5\)
E