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Bunuel
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If 0 < x < 1, is it possible to write x as a terminating dec 15 May 2025, 11:43
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Natansha
Hi Bunuel, could you please explain how is this happening, I couldn't understand the below point, how are we concluding m to be a factor of 6, and n to be a factor of 7

m/n = 6/7, Since m and n are integers, m will be a multiple of 6 (and thereby of 3 too) and n will be a multiple of 7

Bunuel
If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer --> \(24x=m\), where m an integer --> \(x=\frac{m}{24}=\frac{m}{2^3*3}\), If m is a multiple of 3, then the answer is YES, else the answer is NO. Not sufficient.

(2) 28x is an integer --> \(28x=n\), where n an integer --> \(x=\frac{n}{28}=\frac{n}{2^2*7}\), If n is a multiple of 7, then the answer is YES, else the answer is NO. Not sufficient.

(1)+(2) \(x=\frac{m}{2^3*3}=\frac{n}{2^2*7}\) --> \(\frac{m}{n}=\frac{2*3}{7}\) --> m IS a multiple of 3 (as well as n IS multiple of 7). Sufficient.

Answer: C.

Theory:
Reduced fraction \(\frac{a}{b}\) (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only \(b\) (denominator) is of the form \(2^n5^m\), where \(m\) and \(n\) are non-negative integers. For example: \(\frac{7}{250}\) is a terminating decimal \(0.028\), as \(250\) (denominator) equals to \(2*5^2\). Fraction \(\frac{3}{30}\) is also a terminating decimal, as \(\frac{3}{30}=\frac{1}{10}\) and denominator \(10=2*5\).

Note that if denominator already has only 2-s and/or 5-s then it doesn't matter whether the fraction is reduced or not.

For example \(\frac{x}{2^n5^m}\), (where x, n and m are integers) will always be the terminating decimal.

We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \(\frac{6}{15}\) has 3 as prime in denominator and we need to know if it can be reduced.

Questions testing this concept:
https://gmatclub.com/forum/does-the-dec ... 89566.html
https://gmatclub.com/forum/any-decimal- ... 01964.html
https://gmatclub.com/forum/if-a-b-c-d-a ... 25789.html
https://gmatclub.com/forum/700-question-94641.html
https://gmatclub.com/forum/is-r-s2-is-a ... 91360.html
https://gmatclub.com/forum/pl-explain-89566.html
https://gmatclub.com/forum/which-of-the ... 88937.html

Hope it helps.
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m and n are multiples, not factors, of 6 and 7 respectively.

m/n = 6/7 means m and n must be in the ratio 6 to 7 using integers. So m can be 6, 12, 18, etc., and n would be 7, 14, 21, etc., keeping m/n = 6/7. That’s why m must be a multiple of 6 and n a multiple of 7.
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If 0 < x < 1, is it possible to write x as a terminating dec 17 Jan 2026, 05:02
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Hi Sir,

With this approach, we are getting two values when we combine both statement 1 and 2. still answer is correct

Normally in DS Question answer is correct once when statement gives accurate one value.

This question is of Yes or No and both values are giving Yes question Hence answer is C ?


fameatop
If 0 < x < 1, is it possible to write x as a terminating decimal?
(1) 24x is an integer.
(2) 28x is an integer.


Reduced fraction \(\frac{a}{b}\) (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only \(b\) (denominator) is of the form \(2^n5^m\), where \(m\) and \(n\) are non-negative integers

Statement 1- If 24x is an integer than x can take the following values
1/2, 1/3, 1/4, 1/6, 1/8, 1/12, 1/24
Some values of x can be reduced to a terminating decimal (1/2, 1/4, 1/8), while few can not be (1/3,1/6,1/12, 1/24)
Insufficient

Statement 2- If 28x is an integer than x can take the following values
1/2, 1/4, 1/7, 1/14, 1/28
Some values of x can be reduced to a terminating decimal (1/2, 1/4), while few can not be (1/7, 1/14, 1/28)
Insufficient

Statement 1& 2- If both 24x & 28x are integers than x can take the following values
1/2, 1/4
Both of these values of x can be reduced to a terminating decimal
Sufficient

Ans C.

Hope the explanation will help many.
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