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Bunuel
If 1 <= x <= 100, what fraction of values for integer x have the same units digit as x^3?

A) 1/10
B) 1/5
C) 2/5
D) 1/2
E) 3/5



x and x^3 will have the same digit for the number which have unit digit whose cyclicity is either 2 or 1

Cyclicity is the cycles of powers after which the unit digit repeats i.e. Cyclicity of 2 means that unit digit repeats after two higher powers

Cyclicity of 1: The numbers with unit digit {0, 1, 5, 6}
Cyclicity of 2: The numbers with unit digit {4, 9}
Cyclicity of 4: The numbers with unit digit {2, 3, 7, 8}



Numbers from 1 to 10 that have cyclicity 1 or 2 = {0, 1, 4, 5, 6, 9} i.e. 6 numbers

Every 10 consecutive numbers in such sequence will have 6 numbers that will have cyclicity of 1 or 2

hence, total numbers for which x and x^3 will have same unit digit int he given range = 6*10 = 60

Probability of choosing a number of this type = 60/100 = 3/5


Answer: Option E

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At first I didn't understand the "fraction of values" part, then I figured it out:

Count of all possible values that keep the same unit digit when elevated to the third power/Total count of possible values.


Total number of possible values for \(x\): 100. This will be our denominator.

Number of values that keep the unit digit when elevated to the third power: all the numbers that end in {0,1,4,5,6,9} = 6 numbers * 10 different possible ten digits = 60.

\(\frac{60}{100}=\frac{3}{5}\)


Answer E.
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