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kennavalkyrie
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kennavalkyrie
If 11m − n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?

(A) 2m −1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5

Another approach (similar to Bunuel's):

Average = (m + n + p)/3
Replace p with 11m - n, to get:
Average = [m + n + (11m - n)]/3
= 12m/3
= 4m
Answer:
Related Video:

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m+n+p/3
=m+n+11m-n/3
=12m/3
=4m

B
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Arithmetic mean=(m+n+p)/3
From the equation we have
11m-n=p
11m=p+n
Substituting the value pf p+n
AM=12m/3=4m
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kennavalkyrie
If 11m − n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?

(A) 2m −1
(B) 4m
(C) 6m
(D) m/5
(E) 6m/5

We have the following expression for the average of m, n, and p:

(m + n + p)/3

Substituting (11m - n) for p, we obtain:

(m + n + 11m - n)/3 = 12m/3 = 4m

Answer: B
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